Answer:
CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓
Explanation:
We identify the reactants:
CuBr₂ and Pb(CH₃COO)₂
The products will be: Cu(CH₃COO)₂ and PbBr₂
You may know these information:
Salts from acetate are soluble.
Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺
PbBr₂ is formed, so this will be our precipitate
The equation is:
CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓
Answer:
The molarity of the solution is 0.29 ![\frac{moles}{liter}](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7Bliter%7D)
Explanation:
Molarity, or molar concentration, is a measure of the concentration of a solute in a solution, be it some molecular, ionic or atomic species. It is defined as the number of moles of solute that are dissolved in a given volume.
Molarity is calculated as the quotient between the number of moles of solutes and the volume of the solution:
![Molarity=\frac{number of moles of solute}{volume}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bnumber%20of%20moles%20of%20solute%7D%7Bvolume%7D)
Molarity is expressed in units
.
In this case:
- number of moles of solute= 2.1 moles
- volume= 7.3 liters
Replacing:
![Molarity=\frac{2.1 moles}{7.3 liters}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B2.1%20moles%7D%7B7.3%20liters%7D)
Molarity= 0.29 ![\frac{moles}{liter}](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7Bliter%7D)
<u><em>The molarity of the solution is 0.29 </em></u>
<u><em></em></u>
Answer:
3853 g
Step-by-step explanation:
M_r: 107.87
16Ag + S₈ ⟶ 8Ag₂S; ΔH°f = -31.8 kJ·mol⁻¹
1. Calculate the moles of Ag₂S
Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S
2. Calculate the moles of Ag
Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag
3. Calculate the mass of Ag
Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag
You must react 3853 g of Ag to produce 567.9 kJ of heat
Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L