Ask question

Ask question

All categories

3 years ago

14

To report the ____ of an object, we must specify both its speed and its direction .

2 answers:

Alex73 [517]3 years ago

8 0

When you know the object's speed and direction,
you have the complete description of its velocity.

lianna [129]3 years ago

5 0

A vector has both magnitude (size) and direction. So I believe your looking for the word vector component or total.

You might be interested in

How does a battery produce an electric current in a circuit ?

Elza [17]

Answer:

A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

5 0

3 years ago

When does DNA replication occur?

Digiron [165]

Answer:

NA is replicated during the S phase (Synthesis phase) of Interphase.

Hope it helps!!!!!!!!!!

5 0

3 years ago

Read 2 more answers

A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co

Burka [1]

Answer:

4.14 m/s

Explanation:

m¹u¹+m²u²=(m¹+m²)v

5(5)+2(2)=(5+2)v

25+4=7v

29=7v

29/7=v

v=4.14 m/s

3 0

4 years ago

A 0.676 m long section of cable carrying current to a car starter motor makes an angle of 57.7º with the Earth’s 5.29 x 10^−5T f

Studentka2010 [4]

Answer:

The current in the wire under the influence of the force is 216.033 A

Solution:

According to the question:

Length of the wire, l = 0.676 m

$\theta = 57.7^{\circ}$

Magnetic field of the Earth, $B_{E} = 5.29\times 10^{- 5} T$

Forces experienced by the wire, $F_{m} = 6.53\times 10^{-3} N$

Also, we know that the force in a magnetic field is given by:

$F_{m} = IB_{E}lsin\theta$

$I = \frac{F_{m}}{B_{E}lsin\theta}$

$I = \frac{6.53\times 10^{-3}}{5.29\times 10^{- 5}\times 0.676sin57.7^{\circ}$

I = 216.033 A

5 0

3 years ago

On an aircraft carrier, a jet can be catapulted from 0 to 240 km/h in 2.10 s. If the average force exerted by the catapult is 9.

Leya [2.2K]

<h2>Answer</h2>

The answer is 29495.3 kg

<h2>Explanation</h2>

As we know, the Newton's Second Law of Motion

$Force = Mass * Acceleration$

$F = ma$

The F exerted by catapult = 9.35 * $10^5$

The Time is = 2.10 s

Velocity of the catapult = 240 km/h = 66.6 m/s (240*1000 m /3600 s)

The mass of jet = ?

First detrmine the acceleration as

{/tex}Acceleration = Velocity/Time {/tex}

$Acceleration = 66.6 ms^{-1}/2.1 s$

$Acceleration (a) = 31.7 ms^{-2}$

Rearrange the formaula as

$m= F/a$

$m= 9.35 * 10^5 N /31.7 ms^{-2}$

$m = 29495.3 kg$

The mass will be 29495.3 kg

4 0

4 years ago