Question

A 0.676 m long section of cable carrying current to a car starter motor makes an angle of 57.7º with the Earth’s 5.29 x 10^−5T field. What is the current when the wire experiences a force of 6.53 x 10^−3 N?

Answer 1

Answer:

The current in the wire under the influence of the force is 216.033 A

Solution:

According to the question:

Length of the wire, l = 0.676 m

$\theta = 57.7^{\circ}$

Magnetic field of the Earth, $B_{E} = 5.29\times 10^{- 5} T$

Forces experienced by the wire, $F_{m} = 6.53\times 10^{-3} N$

Also, we know that the force in a magnetic field is given by:

$F_{m} = IB_{E}lsin\theta$

$I = \frac{F_{m}}{B_{E}lsin\theta}$

$I = \frac{6.53\times 10^{-3}}{5.29\times 10^{- 5}\times 0.676sin57.7^{\circ}$

I = 216.033 A