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Mekhanik [1.2K]
3 years ago
15

A cylinder contains 250 L of hydrogen gas (H2) at 0.0^∘Cand a pressure of 10.0 atm. How much energy is required to raise the tem

perature of this gas to 25.0^∘C?

Physics
1 answer:
Over [174]3 years ago
8 0

Answer:

The amount of energy needed to raise the temperature of the cylinder by 25 °C is 23.3 KJ of heat.

Explanation:

The step by step calculation can be found in the attachment below. Thank you.

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plz tell fast oktwo paragraphs describing the advantages and disadvantages of living in the town.plz tell​
mars1129 [50]

Answer:

There are advantages and disadvantages to living in a small town. You are likely to have more frequent contact with neighbors in a small town than you would in a larger town or city, so it is important to take into account the pros and cons of having privacy. Also take into consideration other factors, including your plans for a family, the career opportunities, your finances, the schools and entertainment options. Your personality will determine whether a small town offers advantages or disadvantages.

Privacy

Many people who reside in small towns enjoy the closeness of knowing their neighbors and the details of neighbors' lives. If a baby is born, a child is ill or a relative dies, people in small towns often want to know about it and be there for you. This can be an advantage, especially if you are lacking a family of your own or enjoy a great deal of socializing. However, if you would rather keep the details of your life to yourself and turn your nose up at idle gossip, small town living might not be for you.

Finances

Jobs can be hard to come by in small towns. You might be required to commute out of town to work but then return to a peaceful environment at the end of a busy day. Housing might be cheaper in small towns, although commuting costs might be higher. Food and child care expenses might be reduced as people are more likely to have gardens and share produce or take turns watching each other's children.

Recreation

One of the disadvantages of a small town is not being close to amusement parks, zoos or museums. However, people in small towns tend to come together during town picnics, festivals or fairs. Depending on your preferences, small towns might provide a relaxed, slower pace when it comes to entertainment compared to the hustle and bustle of a city, where there is constant movement, commotion and entertainment at every corner.

Schools

In a small town, class sizes are usually smaller and teachers and students can get to know each other and their fellow classmates on a deeper level. Many small towns have schools that receive national academic awards or are the highest achieving district in their states. CNN Money ranked Louisville, Colorado as the number one small town in America in 2011 and the school system is academically ranked among the top three in the Denver area. However, some of these towns noted high taxes as a trade-off for the outstanding school systems.

Explanation:

3 0
3 years ago
What is nuclear fission? why is this process important to stars?
KIM [24]

Nuclear fusion is a reaction in which two or more atomic nuclei come very close and then collide at a very high speed and join to form a new nucleus. This process is important to stars because they get their energy from the nuclear fusion process

4 0
3 years ago
An object is hanging by a string from the ceiling of an elevator. The elevator is moving upward with a constant speed. What is t
xeze [42]

Answer:

The magnitude of the tension in he string is equal to the magnitude of the weight of the object.

Explanation:

According to the Newton's 1st law, An object will remain at rest or in uniform motion in a straight line unless acted upon by an unbalanced force.

In here, the elevator is moving with a constant speed. So the object must have the equal constant speed. Which means, it has a uniform motion. According to Newton's 1st law, the total unbalanced force on the object must be zero . As we know, there are only two forces are on the object and they are,

The tension in string(T)   ,   The weight of the object(W) .

                                  ∴ F    =   0

                                 T  -  W  =   0

So to balanced those forces, the magnitude of the tension in the string must be equal to the magnitude of the weight of  the object.  

       

8 0
3 years ago
In an aqueous solution where the H+ concentration is 1 x 10-6 M, the OH concentration must be:
vesna_86 [32]

Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

6 0
3 years ago
Chapter 21, Problem 009 Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.12
PilotLPTM [1.2K]

Answer:

a) -1.325 μC

b) 4.17μC

Explanation:

First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:

q_1 + q_2 = constant\\q_1_f = q_2_f |Then\\q_1_f + q_2_f = 2q_1_f = q_1_o+q_2_o\\q_1_f = q_2_f = \frac{q_1_o+q_2_o}{2}

We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.

The electrostatic force is equal to:

F_e = k\frac{q_1q_2}{r^2}

K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2

Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:

F_e_f = k \frac{q_1_fq_2_f}{r^2} = k\frac{\frac{q_1_o+q_2_o}{2}\frac{q_1_o+q_2_o}{2}}{r^2} = k\frac{(q_1_o+q_2_o)^2}{4r^2}  \\(q_1_o+q_2_o) = \sqrt{\frac{F_e_f*4r^2}{k}} = \sqrt{\frac{0.0443N *4(0.641m)^2}{9*10^9Nm^2/C^2} } = 2.844 *10^{-6}C \\ q_1_o = 2.844*10^{-6}C - q_2_o

Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:

F_e_o = k\frac{q_1_oq_2_o}{r^2}\\ q_1_oq_2_o = \frac{F_e_o*r^2}{k} = \frac{-0.121N(0.641m)^2}{9*10^9Nm^2/C^2} = -5.524*10^{-12}

(2.844*10^{-6}C - q_2_o)q_2_o = -5.524*10^{-12}\\0 = q_2_o^2 - 2.844*10^{-6}q_2_o - 5.524*10^{-12}

Solving the quadratic equation:

q_2_o = 4.17*10^{-6}C | -1.325 * 10^{-6}C

for this values q_1 wil be:

q_1_o =  -1.325 *10^{-6}C | 4.17*10^{-6}C

So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC

5 0
3 years ago
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