Question

A hollow conducting spherical shell has radii of 0.80 m and 1.20 m, The radial component of the electric field at a point that is 0.60 m from the center is closest to

Answer 1

Complete Question

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Answer:

The electric field at that point is  $E = 7500 \ N/C$

Explanation:

From the question we are told that  

       The  radius of the inner circle is $r_i = 0.80 \ m$

        The  radius of the outer circle is  $r_o = 1.20 \ m$

       The  charge on the spherical shell $q_n = -500nC = -500*10^{-9} \ C$

      The magnitude of the point charge at the center is  $q_c = + 300 nC = + 300 * 10^{-9} \ C$

        The  position we are considering is  x =  0.60 m  from the center

Generally  the  electric field  at the distance x =  0.60 m  from the center  is mathematically represented as

                 $E = \frac{k * q_c }{x^2}$

substituting values  

                  $E = \frac{k * q_c }{x^2}$

where  k is  the coulomb constant with value $k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

     substituting values

                  $E = \frac{9*10^9 * 300 *10^{-9}}{0.6^2}$

                 $E = 7500 \ N/C$