Hi There! :)
An equilibrium constant is not changed by a change in pressurea. True
b. False
False! :P
this can be solve using the formala of free fall
t = sqrt( 2y/ g)
where t is the time of fall
y is the height
g is the acceleration due to gravity
48.4 s = sqrt (2 (1.10e+02 m)/ g)
G = 0.0930 m/s2
The velocity at impact
V = sqrt(2gy)
= sqrt( 2 ( 0.0930 m/s2)( 1.10e+02 m)
V = 4.523 m/s
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The answer is electric current
Answer:
Amplitude will be equal to 0.091 m
Explanation:
Given mass of the slits = 41 gram = 0.041 kg
Frequency f = 1.65 Hz
So angular frequency 
Angular frequency is equal to 

Squaring both side

k = 4.40 N/m
For vertical osculation


A = 0.091 m
So amplitude will be equal to 0.0391 m