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Sidana [21]
3 years ago
5

Briefly explain how an operating system may be described as an "interrupt-driven program." as system calls) from

Computers and Technology
1 answer:
Reptile [31]3 years ago
7 0

Answer: Interrupt-driven program is defined as the program that permits to executes by stopping the execution of the currently running program.The completion of the program is indicated by the interrupt as a signal from assistant action .

Operating system is the system that carries out the functions and task of computer system.It has the major mechanism in which every alteration and changes are remarked such as state of hardware, event alteration, software component changes etc by the interrupt system.

Through interrupt system the operating system conducts new assignment and task for the compensation of changes that occurred in the system by halting the current working. Resources are invoked to fulfill the requirement of the work load.Thus, operating system can act in interrupt driven system's  manner.

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If the speakers are not working on a laptop, what could be the problem besides the speakers?
Elena-2011 [213]

Answer:

Sound card

Explanation:

In computer or laptop music or sound files are stored in digital form. Sound card is the the device that is used to convert the digital form of music into analog to produce the signal that is compatible with speaker or microphone.

If the speakers are not working on the laptop, means there is no sound produced on speakers. It means that sound card is not working properly.

8 0
3 years ago
Write a program, NumberStatistics.java, that reads an unspecified number of integers. The program ends with the input 0. The pro
Lerok [7]

Answer:

Following are the program, which can be below:

import java.util.*; //defining header file

public class NumberStatistics  //defining class NumberStatistics

{

public static void main(String[] arc) //defining main method

{

int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

Scanner ox= new Scanner(System.in); //creating Scanner class Object

System.out.println("Enter positive and negative value with sign and when complete inter 0:"); //print message  

x= ox.nextInt(); //input value from user

while(x!=0) //defining loop to check input value is 0

{

total_number++; // increment value

if(total_number == 1)  //defining conditional statement to check minimum and maximum value

{

max_val = x; //assign value in max  

min_val = x;//assign value in min

}

else  //defining else block

{

if(max_val < x) //check maximum value

{

max_val = x; //assign maximum value

}

if(min_val > x) //check minimum value

{

min_val = x; //assign minimum value

}

}

if(x > 0) //input values  

{

pos_count++; //count positive value

pos_val+=x; // add positive values

}

else  

{

neg_count++;//count negative value

neg_val+=x; // add negative values

}

x = ox.nextInt(); //input values

}

// defining conditionl statement

if(total_number != 0)  // defining if block to print all value

{

System.out.println("positive value average= "+(pos_val/(double)pos_count));

System.out.println("negative values Average= "+(neg_val/(double)neg_count));

System.out.println("all values average= "+(pos_val+neg_val)/(double)total_number);

System.out.println("maximum value = "+max_val+"\n"+" minimum value = "+min_val);

}

else  

{

System.out.println("no positive values found");

System.out.println("no negative values found");

}

}

}

Output:

Enter positive and negative value with sign and when complete inter 0:

12

8

04

22

-22

-5

9

0

positive value average= 11.0

negative values Average= -13.5

all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

The Description of the above java program can be described as follows:

  • In the above code first we import the package for user input, then defines the variable "total_number,max_val,min_val,neg_val,pos_val,neg_count, pos_count,x" to store the value prints its value.
  • In the next step, a scanner class object is created for user input and defines a while loop, that checks input value isn't equal to 0, inside the loop a conditional statement defines that cont and calculates all positive, negative, and all values addition.
  • At the another conditional statement is defines, that prints all value average, and also prints maximum, minimum value.
6 0
4 years ago
White meat and dark meat fish have slightly different nutritional characteristics. What are the nutrition characteristics of dar
Marina CMI [18]

The nutrition characteristics of eating darker meat of fish like Salmon are that it is higher in healthy Omega-3 fats. It is true, however, that as much as it has the highest Omega-3 fats, it is also likely to be highest in any potential toxins.






7 0
3 years ago
Read 2 more answers
Supposethatyoubet$5oneachofasequenceof50independentfairgames. Usethecentrallimittheorem to approximate the probability that you
lions [1.4K]

Answer:

0.119

Explanation:

50 independent fair games

Mean will be 50/2 = 25

Standard deviation of the loosing probability is :

\sqrt{50*0.5*0.5} * 10 = 33.536

we have to loose 33 times out of 50 games.

To find the approximate probability we use z- value table.

z value =  \frac{33-25}{3.35}

z - value = 2.2659

Looking at the z-value table we get 0.119.

8 0
3 years ago
9.10: Reverse ArrayWrite a function that accepts an int array and the array ’s size as arguments . The function should create a
AleksandrR [38]

Answer:

#include <iostream>

using namespace std;

int * reverse(int a[],int n)//function to reverse the array.

{

   int i;

   for(i=0;i<n/2;i++)

   {

       int temp=a[i];

       a[i]=a[n-i-1];

       a[n-i-1]=temp;

   }

   return a;//return pointer to the array.

}

int main() {

   int array[50],* arr,N;//declaring three variables.

   cin>>N;//taking input of size..

   if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..

   return 0;

   for(int i=0;i<N;i++)

   {

       cin>>array[i];//prompting array elements..

   }

   arr=reverse(array,N);//function call.

   for(int i=0;i<N;i++)

   cout<<arr[i]<<endl;//printing reversed array..

   cout<<endl;

return 0;

}

Output:-

5

4 5 6 7 8

8

7

6

5

4

Explanation:

I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.

8 0
3 years ago
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