Answer:
Explanation:
Given that:
The radius of the table r = 16 cm = 0.16 m
The angular velocity = 45 rpm
=
= 4.71 rad/s
However, the relative velocity of the bug with turntable is:
v = 3.5 cm/s = 0.035 m/s
Thus, the time taken to reach the bug to the end is:
t = 4.571s
So the angle made by the radius r with the horizontal during the time the bug gets to the end is:
Now, the velocity components of the bug with respect to the table is:
Also, for the vertical component of the velocity
Answer:
a) the magnitude of the force is
F= Q() and where k = 1/4πε₀
F = Qqs/4πε₀r³
b) the magnitude of the torque on the dipole
τ = Qqs/4πε₀r²
Explanation:
from coulomb's law
E =
where k = 1/4πε₀
the expression of the electric field due to dipole at a distance r is
E(r) = , where p = q × s
E(r) = where r>>s
a) find the magnitude of force due to the dipole
F=QE
F= Q()
where k = 1/4πε₀
F = Qqs/4πε₀r³
b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces
τ = F sinθ × s
θ = 90°
note: sin90° = 1
τ = F × r
recall F = Qqs/4πε₀r³
∴ τ = (Qqs/4πε₀r³) × r
τ = Qqs/4πε₀r²