Answer: E = 1.62*10^-3 v
Explanation:
Given
L = 1.9 m
V = 19 m/s
B = 4.5*10^-5 T
Induced emf can be found by using the formula for induced emf in a moving conductor.
e = blv, where
B is the component of the earth's magnetic field.
L is the width of the car in m
V is the velocity of the car in m/s
E is the induced emf in volts.
E = 4.5*10^-5 * 1.9 * 19
E = 1.62*10^-3 v
The drivers side is more positive, so the charge would remain positive
N
W E
S
Paula has gone 1 km east as the total displacement. The total distance would be 7 km. Why? Well, the difference between displacement and distance is displacement is directional which is why it’s included in velocity and not speed. However, distance is more broad and not as specific.
Answer:
This result is a very good approximation, because R>>d
Explanation:
The capacitance for two parallel flat plates, with surface S, space between them d, is:
This calculation is based on the fact that the electric field is constant between the plates. This only happens if the area of the plates is much larger than the distance between them: S>>d, i.e. R>>d. If we assume these factors, the result has a very good approximation.
Answer:
The maximum speed a subway train can attain between stations is 32.93 m/s.
Explanation:
Given;
maximum tolerable acceleration = 1.39 m/s²
distance between subway train, d = 780 m
The distance available to accelerate between stations = ¹/₂ x 780 m = 390 m
Apply the following kinematic equation to determine the maximum speed;
v² = u² + 2ad
v² = 0 + 2ad
v² = 2(1.39)(390)
v² = 1084.2
v = √1084.2
v = 32.93 m/s
Therefore, the maximum speed a subway train can attain between stations is 32.93 m/s.
Answer:
Explanation:
The problem is based on the concept of Doppler's effect of em wave .
Expression for apparent frequency can be given as follows
n = N x (V - v ) / ( V + v )
n is apparent frequency , N is real frequency , V is velocity of light and v is velocity of cloud.
n = 6 x 10⁹ ( 3 x 10⁸ - 8.52 ) / ( 3 x 10⁸ + 8.52 )
= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸ + 8.52 )⁻¹
= 6 x 10⁹ ( 3 x 10⁸ ) ( 3 x 10⁸)⁻¹ ( 1 + 8.52/3 x 10⁸ )⁻¹
= 6 x 10⁹ ( 1 - 8.52/3 x 10⁸ )
= 6 x 10⁹ - 6 x 10⁹x 8.52/ (3 x 10⁸ )
= 6 x 10⁹ 1 - 170 .
So change in frequency = 170 approx.