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Effectus [21]
3 years ago
11

Photoelectrons with a maximum speed of 7.00 · 105 m/s are ejected from a surface in the presence of light with a frequency of 8.

00 · 1014Hz. If the mass of an electron is 9.1 · 10-31 kg, calculate the maximum kinetic energy of a single electron, in joules.
_____ J


6.3 x 10-25
4.4 x 10-19
3.2 x 10-25
2.2 x 10-19
Physics
1 answer:
lord [1]3 years ago
4 0
This is just testing your ability to recall that kinetic energy is given by: 

<span>k.e. = ½mv² </span>

<span>where m is the mass and v is the velocity of the particle. </span>

<span>The frequency of the light is redundant information. </span>

<span>Here, you are given m = 9.1 * 10^-31 kg and v = 7.00 * 10^5 m/s. </span>
<span>Just plug in the values: </span>

<span>k.e. = ½ * 9.1 * 10^-31 * (7.00 * 10^5)² </span>
<span>k.e. = 2.23 * 10^-19 J 
so it will be d:2.2*10^-19 J</span>
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Tresset [83]

Answer:

<h2>507 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.5 \times  {26}^{2}  \\  =  \frac{1}{2}  \times 1.5 \times 676 \\  = 1.5 \times 338  \\ = 507

We have the final answer as

<h3>507 J</h3>

Hope this helps you

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Answer:

Explanation:

a )

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h = .04 m

4 cm .

=

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