A 0.04358 g sample of gas occupies 10.0-ml at 292.0 k and 1.10 atm. upon further analysis, the compound is found to be 25.305% c
2 answers:
PV = mRT: gas law.
M = : molecular mass
Use: M =
<em>Where </em>
m = 0.04343 g
P = 1.10 atm
V = 0.0100 L
R = 0.08205746 (14) L atm K mole
T = 293.0 K
M: the molecular mass of the gas.
<em>Then take the mass of this molecule, the molecular mass of the atom (C & Cl), and also the proportion of mass given to search out the amount of moles per mole of gas. </em>
<h2>Further explanation</h2>
The chemical formula is a component of a formula, that has associate understanding of a substance that determines the kind and a relative range of atoms that area unit in this substance. Or in different languages, a formula are often given that contains data concerning the atoms that form up a selected chemical composition.
Chemical formula is split into 2 specifically chemical formula and formula. The formula announces that the formula mentioned will prove the molecules of the mix atoms. whereas the formula is that the original formula of a composition. The chemical formula are often determined if the relative molecular mass is thought.
Learn more
Gas molecular calculations brainly.com/question/6250579
Molecular Mass brainly.com/question/7233727
Details
Class: highschool
Subject: Chemistry
Keywords: Mole, Formula, Mass
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<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
<u>Explanation:</u>
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
The equation given by Henry's law is:
......(1)
where,
= solubility of carbon dioxide in water = 0.161 g/100 mL
= Henry's constant = ?
= partial pressure of carbon dioxide = 760 mmHg
Putting values in equation 1, we get:
Now, calculating the pressure of carbon dioxide using equation 1, we get:
= solubility of carbon dioxide in water = 0.886 g/100 mL
= Henry's constant = 4720.5 g.mmHg/100 mL
= partial pressure of carbon dioxide = ?
Putting values in equation 1, we get:
Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
Answer:
0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂
Explanation:
In first place, the balanced reaction between Mg and O₂ is:
2 Mg + O₂ ⇒ 2 MgO
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:
- Mg: 2 moles
- O₂: 1 mole
- MgO: 2 moles
Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?
moles of MgO= 0.250
<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>