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3 years ago

Which of the following correctly identifies the composition of an oxygen atom?

2 answers:

7 0

Oxygen has the atomic number 8, which eliminates options B and D right away. Any neutral atom, including the oxygen atom, has the same number of protons and electrons, meaning the number of electrons is also 8. If you're still not sold, the oxygen atom has a mass number of 16, which is the sum of the protons and neutrons in the atom, meaning there have to be 8 neutrons as well. The answer is option A.

aleksandrvk [35]3 years ago

3 0

The composition of an oxygen atom is: A) 8 protons, 8 electrons, and 8 neutrons.

<h3>Further Explanation</h3>

To determine how many of the subatomic particles are in the atom, the atomic number is used.

Atomic number is the number that gives the atom its identity and can be found in the periodic table. It gives the number of protons in an atom. It can be observed that the atomic number of the elements are increasing by one unit as you go from left to right.

<em>The atomic number of oxygen is 8, therefore, it has 8 protons.</em>

<em>In a neutral (uncharged atom), the number of protons and electrons are equal.</em>

<em>Hence, oxygen also has 8 electrons.</em>

In the most simple periodic table of elements, the atomic number is usually the smaller number written in the tile for each element. The larger number is the mass number.

The difference between the larger mass number and the smaller atomic number is the number of neutrons:

<em>Number of Neutrons = Mass Number - Atomic Number</em>

The mass number of oxygen is 16. We can use the atomic number and the mass number to get the number of neutrons using the equation above:

<em>Number of Neutrons = 16 – 8</em>

<em>Number of Neutrons = 8</em>

Therefore, it has been determined that the an oxygen atom has 8 protons, 8 electrons and 8 neutrons.

<h3>Learn More</h3>

Periodic Table brainly.com/question/2376134

Isotopes brainly.com/question/2757829

<h3>Keywords: protons, neutrons, electrons, mass number, atomic number</h3>

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3 years ago

Carbon tetrachloride, CCl4, once used as a cleaning fluid and as a fire extinguisher, is produced by heating methane and chlorin

Elena-2011 [213]

Answer:

1.882 g

Explanation:

Data Given

mass of Cl₂ = 33.4 g

mass of CH₄ = ?

Reaction Given:

CH₄+ 4Cl₂ --------→ CCl₄ + HCl

Solution:

First find the mass of CH₄ from the reaction that it combine with how many grams of Chlorin.

Look at the balanced reaction

CH₄ + 4Cl₂ --------→ CCl₄ + 4HCl

1 mol 4 mol

So 1 mole of CH₄ combine with 4 moles of Cl₂

Now

convert the moles into mass for which we have to know molar mass of CH₄ and Cl₂

Molar mass of Cl₂ = 2 (35.5)

Molar mass of Cl₂ = 71 g/mol

mass of Cl₂

mass in grams = no. of moles x molar mass

mass of Cl₂ = 4 mol x 71 g/mol

mass of Cl₂ = 284 g

Molar mass of CH₄= 12+ 4(1)

Molar mass of CH₄= 16 g/mol

mass of CH₄

mass in grams = no. of moles x molar mass

mass of CH₄= 1 mol x 16 g/mol

mass of CH₄ = 16 g

So,

284 g of Cl₂ combine with 16 g of methane ( CH₄ ) then how many grams of CH₄ is needed to combine with 33.4 g of Cl₂

Apply unity Formula

284 g of Cl₂ ≅ 16 g of methane ( CH₄ )

33.4 g of Cl₂ ≅ X g of methane ( CH₄ )

By cross multiplication

X g of methane ( CH₄ ) = 16 g x 33.4 g / 284 g

X g of methane ( CH₄ ) = 1.88 g

1.882 g of methane (CH₄) will needed to combine with 33.4 g of Cl₂

methane (CH₄) = 1.882 g

5 0

3 years ago

Balance the following chemical equation<br> Na+I2->NaI

jenyasd209 [6]

Balanced equation : 2Na+I₂⇒2NaI

<h3>Further explanation </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Na+I₂⇒NaI

Give coefficient :

aNa+bI₂⇒NaI

Make an equation :

Na, left=a, right=1⇒a=1

I, left=2b, right=1⇒2b=1⇒b=0.5

Equation becomes :

Na+0.5I₂⇒NaI x 2

2Na+I₂⇒2NaI

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3 years ago

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4 years ago