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Alchen [17]
3 years ago
9

@kikatkraken This is the energy of an object while it is in motion.

Physics
1 answer:
ZanzabumX [31]3 years ago
8 0
A! Kinetic energy is energy moving!
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A chef fills 50cm3 container with 250g of cooking oil what is the density of the oil?
Flura [38]

Given that,

Mass, m = 250 g

Volume of the container, V = 50 cm³

To find,

The density of the oil.

Solution,

Density = mass/ volume

The computation for density is as follows :

\rho =\dfrac{m}{V}\\\\\rho =\dfrac{250\ g}{50\ cm^3}\\\\=5\ g/cm^3

So, the density of the oil is 5\ g/cm^3.

8 0
2 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.360 mm wide. The diffraction pattern is observed
Bumek [7]

Answer:

a) 0.0130 m

b') w' = =6.46*10^{-3] m

Explanation:

given data:

\lambda of light = 633 nm

width of siit a =0.360 mm

distance from screen = 3.75 m

a) the first minima is located at

sin\theta = \frac{\lambda}{a}

              == \frac{633 *10^{-9}}{.360*10^{-3}}

           \theta = 0.100

y_1 = dtan\theta_1 = 3.75*tan(0.100) = 6.54 *10^{-3} m

with of central fringe  = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m

b)

width of the first bright fringe on either side of the central one = w' = y_2 -y_1

calculation for y_2

sin\theta = 2\frac{\lambda}{a}

              = = 2*\frac{633 *10^{-9}}{.360*10^{-3}}

             \theta  = 2*0.100 = 0.200

y_2 = dtan\theta_1 = 3.75*tan(0.200) =0.0130 m

w' = 0.0130  -6.54 *10^{-3}

w' = =6.46*10^{-3] m

6 0
3 years ago
The analysis of how people relate to each other is known as
Colt1911 [192]
Anthropology 

Hope this helps! ^-^
4 0
3 years ago
PLZ Help Me I give you brainlist also NO LONKS OR I REPORT and Have a gr8 day my peeps
Sergio039 [100]

Answer:

the answer is a because I saw it in a syllabus

3 0
3 years ago
A monkey has a bit of a heavy for on the gas pedal. As soon as the light turns green the monkey pushes the gas pedal to the floo
Andrei [34K]

Answer:

s=6.86m/s^2

Explanation:

Hello,

In this case, considering that the acceleration is computed as follows:

a=\frac{v_{final}-v_{initial}}{t}

Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:

a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2

Regards.

3 0
3 years ago
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