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pickupchik [31]
3 years ago
6

Science 5.13 unit 5 PLZZZ HELPPPP 99 point

Chemistry
2 answers:
sergey [27]3 years ago
8 0

was is your question on it and what grade level are you?


Mademuasel [1]3 years ago
5 0
Please specify the question
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Please I need help with questions 1-4 and can you check if I plot it correct in to the punnet square for questions 1-4 and I nee
fgiga [73]
Number 1 is incorrect, the genotypes are given to you. You need to use GG and gg. The outcome would be 100% Gg.

Number 2 is incorrect, the genotypes are given to you. You need to use Gg and Gg. The outcome would be 25% gg, 25% GG, and 50% Gg.

Number 3 is incorrect, the genotypes are given to you. You need to use TT and tt. The outcome would be 100% Tt.

Number 4 is incorrect, the genotypes are given to you. You need to use RR and rr. The outcome would be 100% Rr.

Please read the directions and use the genotypes they give you! The information is all there for you, you just need to put it in correctly. If you're still having trouble understanding how to do this, feel free to message me and I'd be happy to help you.
8 0
3 years ago
I know the photo trash but i need answers for the top middle and last question please :)
Firlakuza [10]

Answer:

Middle: Self heating containers are really expensive but are useful because they are easy to use, portable, and can be recycled, unlike a camp stove which is not as easily moved.

Explanation:

i neeed a better image for the first an last boo<3

6 0
2 years ago
Can anyone help me with Science Grade 6 questions , soon as possible?
jolli1 [7]
Well depending on how many people on one side of the family, you would inherite  their trait more commonly.
6 0
3 years ago
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
Too much ___________ can slow and eventually stop the heart, and supplements should be taken only under the care of a physician.
Marina86 [1]
<span>Too much B. potassium can slow and eventually stop the heart, and supplements should be taken only under the care of a physician. </span>
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3 years ago
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