If you have a polyatomic anion of Ammonium (NH41+), how many valence electrons must your Lewis Structure have?
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Answer:
40.02 calories
Explanation:
V = 10 mL = 10g
we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.
Formula that ties it together: Q = mc∆t
where,
Q = energy absorbed by water
m = mass of water
c = specific heat of water (constant)
∆t = temperature change
Q = (10 g) x (4.186 J/g•°C) x (4°C)
Q = 167.44 J
Joules to Calories:
167.44 J x 1 cal/4.184 J = 40.02 calories
(makes sense as in image it is close to the value).
Mass of (NH₄)₂U₂O₇ : 410.05 kg
<h3>Further explanation</h3>Reaction
2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄
MW UO₂SO₄ : 366.091
MW (NH₄)₂U₂O₇ : 624.131
MW H₂O : 18.0153
MW NH₃ : 17.0306
mol of 100 kg water :
mol of 100 kg ammonia :
mol of UO₂SO₄ :
Limiting reactants : smallest mol ratio(mol : coefficient)
UO₂SO₄ ⇒ Limiting reactants
mol (NH₄)₂U₂O₇ : mol UO₂SO₄
mass (NH₄)₂U₂O₇