Answer: The period of the subsequent simple harmonic motion is 1.004 sec.
Explanation:
The given data is as follows.
Mass of disk (m) = 2.2 kg, radius of the disk (r) = 61.2 cm,
Formula to calculate the moment of inertia around the center of mass is as follows.
= 
= 0.412 
Also,
Distance between center of mass and axis of rotation (d) = r = 0.612 m
Moment of inertia about the axis of rotation (I)
I = 
I = 
= 0.339 
Now, we will calculate the time period as follows.
T = 
T = 
T = 1.435 sec
T = 
= 1.004 sec
Thus, we can conclude that the period of the subsequent simple harmonic motion is 1.004 sec.
The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy <em>PE</em> :
<em>PE</em> = <em>m g h</em>
<em>PE</em> = (2.0 kg) (9.8 m/s²) (3.0 m)
<em>PE</em> = 58.8 J
Energy is conserved throughout the block's descent, so that <em>PE</em> at the top of the curve is equal to kinetic energy <em>KE</em> at the bottom. Solve for the velocity <em>v</em> :
<em>PE</em> = <em>KE</em>
58.8 J = 1/2 <em>m v</em> ²
117.6 J = (2.0 kg) <em>v</em> ²
<em>v</em> = √((117.6 J) / (2.0 kg))
<em>v</em> ≈ 7.668 m/s ≈ 7.7 m/s
<span>During the reading of a blueprint, a general tolerance
pertains to all dimensions that are not independently identified. All tolerances
are +\- .030. General tolerances are mostly found in the blueprint’s set of
information. Let’s say for example, a compact tolerance is required, then a
specific tolerance is considered for specific areas of the blueprint. These
kinds of tolerances are commonly found along the affected area.</span>
(a) The spring constant is 500 N/m.
(b) The extension of the spring when 25 N force is applied is 0.05 m.
(c) The applied force to cause an extension of 5 mm is 2.5 N.
The given parameters:
- Applied force, F = 10 N
- Extension of the spring, x = 20 mm
The spring constant is calculated as follows;
The extension of the spring when 25 N force is applied is calculated as follows;
The applied force to cause an extension of 5 mm is calculated as follows;
Learn more about Hook's law here: brainly.com/question/12253978
= Joules ÷ (0.5×Kilograms)
14J ÷ 8.5 = 1.64705882
Remember, 1.64705882 = v², so we need to find the square root.
The square root of 1.64705882 is 1.283377894464448
Hope this helps!
