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3 years ago

Which has more friction? wax paper, aluminum foil, wood

Physics

2 answers:

Nadusha1986 [10]3 years ago

5 0

The answer to this is aluminum foil.

aalyn [17]3 years ago

4 0

My best guess would be Aluminum foil.

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Help meh in this question plzzz

iragen [17]

The Moment of Inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

Where:

$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):

$\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}$

$m = \frac{1}{2}\cdot M$

And the resulting equation is:

$I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)$

$I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}$

$I = \frac{15}{32}\cdot M\cdot R^{2}$

The moment of inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Please see this question related to Moments of Inertia: brainly.com/question/15246709

5 0

3 years ago

Given:A=6x-2y B:-4x-8y C:-3x+9y. Commute A+B-C

DedPeter [7]

A+B-C
A = 6x - 2y
B = -4x - 8y
C = -3x + 9y

(6x - 2y) + (-4x - 8y) - (-3x + 9y)
(6x - 2y) + (-4x - 8y) + (3x - 9y)
2x -10y + (3x - 9y)

5x - 19y

8 0

3 years ago

A student, standing on a scale in an elevator at rest, sees that his weight is 840 N. As the elevator rises, his weight increase

ololo11 [35]

As per FBD while its accelerating upwards

we can say that

$F_n - mg = ma$

here normal force is given as

$F_n = 1050 N$

$W = 840 N$

now mass is given as

$m(9.8) = 840$

$m = 85.7 kg$

now we will have

$1050 - 840 = 85.7 \times a$

$a = 2.45 m/s^2$

Now while accelerating downwards we can say by FBD

$mg - F_n = ma$

again plug in all values

$840 - 588 = 85.7 \times a$

$a = 2.94 m/s^2$

5 0

3 years ago

If you know the distance traveled and the time traveled, you can determine an object’s

lara31 [8.8K]

If I tell you that I traveled 30 miles in the last 2 hours, the only thing you can calculate is my average speed during those two hours. You can't tell anything about my acceleration or the direction in which I traveled.

3 0

3 years ago

A fisherman notices that wave crests pass the bow of his anchored boat every 5.0 s. He measures the distance between two crests

Flauer [41]

Answer: |

Read More V

Explanation:

Haha. You FOOL. Unless you have bought the dumb brainly plus you had to watch an AD for NO ANSWER.

8 0

4 years ago