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Serga [27]
3 years ago
11

A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance will the ball have falle

n after 3 seconds?
Physics
1 answer:
adell [148]3 years ago
5 0

The relevant equation to use here is:

y = v0 t + 0.5 g t^2

where y is the vertical distance, v0 is initial velocity = 0, t is time, g = 9.8 m/s^2

 

y = 0 + 0.5 * 9.8 * 3^2

<span>y = 44.1 meters</span>

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If 10 waves pass a point each second and their wavelength is 30m, what is their speed?
svet-max [94.6K]

Answer:

300m/s

Explanation:

velocity = frequency(wavelength)

Since 10 waves pass a point each second, frequency is 10

therefore, speed = (10)(30 = 300m/s

5 0
3 years ago
At which point on the image to the right would the ball have the greatest velocity if it moved from A to G.
marusya05 [52]

Answer:

It would be A, because it is has more height in which the potential energy would be greater.

4 0
3 years ago
Jasmine is late to science class and misses the very beginning of notes for the day. These are Jasmine’s notes: –Round objects t
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Answer:

d

Explanation:

8 0
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Read 2 more answers
It's nighttime, and you ve dropped your goggles into a 3.2-m-deep swimming pool. If you hold a laser pointer 0.90 m above the ed
yanalaym [24]

Answer:

The distance of the goggle from the edge is 5.30 m

Explanation:

Given:

The depth of pool (d) = 3.2 m

let 'i' be the angle of incidence

thus,

i = tan^{-1}(\frac{2.2}{0.90})

i = 67.75°

Now, Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

where,

r is the angle of refraction

n₁ is the refractive index of medium 1 = 1 for air

n₂ is the refractive index of medium 1 = 1.33 for water

now,

1 × sin 67.75° = 1.33 × sin(r)

or

r = 44.09°

Now,  

the distance of googles = 2.2 + d×tan(r)  = 2.2 + (3.2 × tan(44.09°) = 5.30 m

Hence, <u>the distance of the goggle from the edge is 5.30 m</u>

5 0
3 years ago
A person with mass 65 kg, standing still, throws an object at 4 m/s. If the
fenix001 [56]

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(65 kg) (0 m/s) + m (0 m/s) = (65 kg) (-3.5 m/s) + m (4 m/s)

m ≈ 57 kg

7 0
3 years ago
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