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Serga [27]
3 years ago
11

A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance will the ball have falle

n after 3 seconds?
Physics
1 answer:
adell [148]3 years ago
5 0

The relevant equation to use here is:

y = v0 t + 0.5 g t^2

where y is the vertical distance, v0 is initial velocity = 0, t is time, g = 9.8 m/s^2

 

y = 0 + 0.5 * 9.8 * 3^2

<span>y = 44.1 meters</span>

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