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3 years ago

These materials would result in horizontally polarized light.

1 answer:

7 0

The correct answers among all the other choices are D.) reflection from wet asphalt and E.) refraction from a water surface. These materials would result in horizontally polarized light. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.

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The average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km. How much

aleksklad [387]

Answer:

Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

Explanation:

We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.

We will use Kepler's Law to solve our given problem.

$\frac{(T_1)^2}{(T_2)^2}=\frac{(r_1)^3}{(r_2)^3}$

Upon substituting our given values, we will get:

$\frac{(T_1)^2}{(T_2)^2}=\frac{(238,000)^3}{(1,222,000)^3}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272000000000}{1824793048000000000}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272}{1824793048}$

$\frac{(T_1)^2}{(T_2)^2}=0.0073878361246365$

Taking square root of both sides, we will get:

$\frac{T_1}{T_2}=\sqrt{0.0073878361246365}$

$\frac{T_1}{T_2}=0.0859525225030452495$

$\frac{T_2}{T_1}=\frac{1}{0.0859525225030452495}$

$\frac{T_2}{T_1}=11.634329870476699\approx 11.634$

$T_2=11.634\cdot T_1$

This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.

So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

8 0

3 years ago

A symbol on a compass or map that is circular with graded points for the direction is commonly known as a _________. question 13

son4ous [18]

Answer;

-Compass Rose

A symbol on a compass or map that is circular with graded points for the direction is commonly known as a compass rose.

Explanation;

The Earth is a magnet that can interact with other magnets such that, the north end of a compass magnet is drawn to align with the Earth's magnetic field.

A compass rose is a figure on a compass, map, nautical chart, or monument used to display the orientation of the cardinal directions (north, east, south, and west) and their intermediate points. It is a feature on a map that also tells people what direction to go to find certain places on the map

7 0

3 years ago

Read 2 more answers

What are some examples for number 4?

lidiya [134]

I would love to help you, but the picture is in a difficult position to read.

5 0

3 years ago

I have a question

Anarel [89]

nobody ships them im sorry

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3 years ago

Read 2 more answers

FIGURE 2 shows a constant force, F of magnitude 20N pulled a light cord wrapped around a pulley to lift a bucket of mass 1.53kg.

slava [35]

(a) $14.3 rad/s^2$

The angular acceleration of the pulley can be found by using the equivalent of Newton's second law for rotational motions:

$\tau = I \alpha$ (1)

where

$\tau$ is the net torque on the pulley

$I=0.385 kg m^2$ is the moment of inertia of the pulley

$\alpha$ is the angular acceleration

First, we need to find the net torque. The torque exerted by the force F (forward) is:

$\tau_t = F r = (20 N)(0.330 m)=6.6 Nm$

While the frictional torque (backward) is $\tau_f = 1.1 Nm$ . So, the net torque is

$\tau = \tau_t - \tau_f=6.6 - 1.1 = 5.5 Nm$

Now, re-arranging eq.(1), we find the angular acceleration:

$\alpha = \frac{\tau}{I}=\frac{5.5}{0.385}=14.3 rad/s^2$

(b) $4.72 m/s^2$

Assuming that the string holding the bucket is inextensible, the bucket should have the same linear acceleration of a point on the edge of the pulley, which is given by

$a= \alpha r$

where

$\alpha=14.3 rad/s^2$ is the angular acceleration

r = 0.330 m is the radius of the pulley (the distance of a point at the edge from the centre)

Substituting into the equation, we find

$a=(14.3)(0.330)=4.72 m/s^2$

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3 years ago