The maximum electromotive force induced in the coil by the generator is 56.45 V.
<h3>
Maximum electromotive force induced in the coil</h3>
emf(max) = NAB/t
where;
- N is number of turns
- A is area
- B is magnetic field
- t is time
Substitute the given parameter and solve for maximum electromotive force induced in the coil.
Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²
emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)
emf(max) = 56.45 V
Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.
Learn more about electromotive force here: brainly.com/question/24158806
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Answer:
HP = 27.08 hp
Explanation:
The complete question has a theoretical flow rate of 18.2 GPM. So, to find the input horsepower, we will use the following formula:
HP = QP/1714(E)
where,
HP = Input Horse Power = ?
Q = Volume Flow Rate in Gallons Per Minute (GPM) = 18.2 GPM
P = Outlet Pressure in psi = 2372 psi
E = Mechanical Efficiency = 0.93
Therefore,
HP = (18.2 GPM)(2372 psi)/(1714)(0.93)
<u>HP = 27.08 hp</u>
Basically a distance multiplied by a weight that is equal to the distance that is going to be multiplied by the weight. (for the equation we will use X for the distance).
equation: 4 x1 20 = ? x 80
Now step one: 4(120) = X(80)
Or another way is 480 = 80X
480/80 = X
48/8= X
X = 6
I hope this could help! Sorry if it didn't make much sense otherwise!
Answer:
B. physics and engineering
Explanation:
Biomechanics is the study of mechanical laws and living organisms. Hence, it comprises of the interrelationships between physics and engineering.
