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dedylja [7]
3 years ago
10

How many moles are there in 7.50 x 10^23 atoms of iron?

Chemistry
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer:

1.25 mol

Explanation:

1 mol ---- 6.02*`0^23 atoms

7.50*10^23 atoms * 1 mol/6.02*10^23 atoms = 1.25 mol

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If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?
sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2HgO\rightarrow 2Hg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2HgO = Total mass of 2Hg+O_2

As we are given :

The mass of HgO = 25.3 grams

The mass of Hg = 23.4 grams

So,

2\times 25.3g=2\times 23.4g+\text{Mass of }O_2

50.6g=46.8g+\text{Mass of }O_2

\text{Mass of }O_2=3.8g

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0
3 years ago
which one of the following groups are decomposers a. algae b. protist c. fungi d. green plants e. photosynthetic bacteria
alukav5142 [94]

Answer:c

Explanation:

7 0
2 years ago
What is the change in boiling point for a 0.615m solution of Mgl2 in water?
ivanzaharov [21]

Answer :  The change in boiling point is, 0.94^oC

Explanation :

Formula used :

\Delta T_b=i\times K_f\times m

where,

\Delta T_b = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

K_f = boiling point constant for water = 0.51^oC/m

m = molality  = 0.615 m

Now put all the given values in this formula, we get

\Delta T_b=3\times (0.51^oC/m)\times 0.615m

\Delta T_b=0.94^oC

Therefore, the change in boiling point is, 0.94^oC

4 0
3 years ago
A container is at a pressure of 3 atm and a temperature of 280K. What is the new temperature when the pressure is reduced to 1.5
GenaCL600 [577]

Answer:

140 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 3 atm
  • Initial temperature of the gas (T₁): 280 K
  • Final pressure of the gas (P₂): 1.5 atm
  • Final temperature of the gas (T₂): ?

Step 2: Calculate the final temperature of the gas

We have a gas whose pressure is reduced. If we assume an ideal behavior, we can calculate the final temperature of the gas using Gay-Lussac's law.

T₁/P₁ = T₂/P₂

T₂ = T₁ × P₂/P₁

T₂ = 280 K × 1.5 atm/3 atm = 140 K

6 0
3 years ago
How to solve 5gNaCl= MolE NaCl
valentinak56 [21]

0.086mole

Explanation:

The problem is very simple. It involves conversion from mass to number of moles of NaCl

What is mole?

 A mole is a unit of measuring chemical substances. It is the amount that contains the avogadro's number of particles.

How is it related and can be converted from mass;

 

Number of moles of a substance = \frac{mass}{molar mass}

Since we know the mass, we can find the molar mass and put into this equation;

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Number of moles of NaCl = \frac{5}{58.5}  = 0.086mole

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

4 0
3 years ago
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