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dedylja [7]
3 years ago
10

How many moles are there in 7.50 x 10^23 atoms of iron?

Chemistry
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer:

1.25 mol

Explanation:

1 mol ---- 6.02*`0^23 atoms

7.50*10^23 atoms * 1 mol/6.02*10^23 atoms = 1.25 mol

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a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction

Explanation:

<em>Ferrous Sulphate</em>(FeSO4)<em> is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide </em>(SO_3)<em>, Sulphur Dioxide </em>(SO_2)<em>  as well as Ferric Oxide </em>(Fe_2O_3)<em>.</em>

<em>We can hence, frame a skeletal equation of this reaction and try to balance it.</em>

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FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3

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<em>2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:</em>

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