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kvv77 [185]
3 years ago
14

135,000 kilometers = how many miles?

Physics
1 answer:
DerKrebs [107]3 years ago
5 0
1 mile = 1.609 km

(135,000 km) x (1 mile / 1.609 km)  =  83,885.1 miles
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The human body is a system of systems that rely on each other to sustain a life. Explain how.
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At what common temperature will a block of wood and a block of metal both feel neither hot nor cold to the touch ?
Anastaziya [24]

When you touch an object and heat flows OUT of it, INTO your finger, you say the object feels hot.

When you touch an object and heat flows INTO it, OUT of your finger, you say the object feels cold.

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6 0
3 years ago
A person must pull a rope 20 meters with a force of 200 N what is the work input?
tatiyna
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4 0
3 years ago
You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee
Archy [21]

Answer:

V = 4.81 V

Explanation:

  • As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
  • We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

        V_{rint} = I* r_{int}

  • The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

       V = V_{b} - V_{rint}  = 5.03 V = 6.0 V - 0.383 A* r_{int}

  • We can solve for rint, as follows:

         r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega

  • When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

       V = V_{b} - V_{rint}  = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V

  • As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.
5 0
3 years ago
A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times be
ra1l [238]

Answer:

Explanation:

Given,

initial angular speed, ω = 3,700 rev/min

                                      = 3700\times \dfrac{2\pi}{60}=387.27\ rad/s

final angular speed = 0 rad/s

Number of time it rotates= 46 times

angular displacement, θ = 2π x 46 = 92 π

Angular acceleration

\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}

\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}

\alpha = -259.28 rad/s^2

3 0
3 years ago
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