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sukhopar [10]
3 years ago
15

Push-and-pull factors contribute to _____. economics politics migration education

Physics
1 answer:
kaheart [24]3 years ago
7 0

c) migration

Push factors are the reasons why people leave an area. Pull factors are the reasons why people move to a particular area.

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How much work does a man perform on a lawnmower if he applies 25 N of force to push it 100 meters
zmey [24]
  • Force=25N
  • Displacement=100m

\\ \sf\longmapsto Work\:Done=Force\times Displacement

\\ \sf\longmapsto Work\:Done=25(100)

\\ \sf\longmapsto Work\:Done=2500J

3 0
3 years ago
Read 2 more answers
A probe orbiting Venus exerts a gravitational force of 2.58 × 103 N on Venus. Venus has a mass of 4.87 × 1024 kg. The mass of th
Westkost [7]
<h3>The correct answer is:</h3><h2>9.08 x 10⁶ meters.</h2><h2 /><h3>Explanation:</h3>

Fg = 2.58 x 10³ N


Mv = 4.87 x 10²⁴ Kg


Md = 655 Kg


So, Fg = G Mv Mp / r²


By putting in the values,


r² = 8.2466 x 10¹³


<h2>r = 9.08 x 10⁶ meters.</h2>
3 0
3 years ago
Read 2 more answers
Physics A-Level, both of these questions
podryga [215]
I can only help you with question 7
B is the right answer.
A is wrong because when the angle is critical angle the light leaves medium 1 parallel to the surface.
C is wrong because light reflects only when travelling from a denser to a rarer/less dense medium.speed of light is lower in denser medium.
D is wrong because the frequency of the light doesn't change when travelling from one medium to another.
8 0
3 years ago
You throw a ball straight up from the edge of a cliff. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
Levart [38]

Answer:

y = 3.159 m

Explanation:

Using the second equation of motion.

s = ut + 0.5at^2 .......1

Since the ball is thrown upward the acceleration due to gravity act against it.

Given:

distance s = y

Initial speed u = 12.0 m/s

Time t = 0.30 s

Acceleration a = -g = -9.8m/s^2

Equation 1 becomes;

y = ut - 0.5at^2

Substituting the given values. We have;

y = 12.0(0.30) - 0.5(9.8 × 0.3^2)

y = 3.6 - 0.441

y = 3.159 m

8 0
3 years ago
What’s the frequency for problem #10?
Kaylis [27]

The answers penciled in on the sheet are fine ... 1500 Hz and 0.0006 sec.

If you want to get super-technical about it, you could count the number of full cycles on the WHOLE graph, from one side to the other.  At the right end, near 0.01 sec, you can notice an extra 1/4 of a cycle there.  So it's actually 15 and 1/4 cycles in 0.01 sec.

That makes the frequency (15.25 cycles) / (0.01 sec) = 1,525 Hz .

and the period ( second / 1525) = 0.000656... second.

But I think it would be OK if you didn't do that, and just call it 1500 Hz and 0.0006s.

The difference is only 1.6% , and the engineer in me says that's not enough to worry about.

3 0
3 years ago
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