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cupoosta [38]
3 years ago
12

If we observe a star over 6 months and obtain a parallax angle (p) for the star, how can we calculate the distance to the star?

Physics
2 answers:
OLEGan [10]3 years ago
5 0
Write the angle in seconds (1/3600 of a degree). It'll be less than 1 second for any star. Now, take the reciprocal of the number of seconds. (1/seconds). That number is the distance to the star, in "parsecs". 1 parsec = about 3.26 light years. The nearest star, Alpha Centauri, has a parallax of 0.75481 second. The reciprocal of that number is 1.3248 . Multiply that by 3.26156 light years per parsec, and you get 4.32103 light years. The awesome thing about it is how in the world they were able to measure 0.75481 of a second of parallax. That's 0.00020967 of one degree ! And they have to measure it between two times that are six months apart ! ! And that's the nearest star, with the greatest parallax ! ! ! Totally incredible.
blsea [12.9K]3 years ago
5 0

Question 1  

.

3 out of 3 points

   

 

A light-year is best defined as ________.

 

Selected Answer:  

Correct  

the distance that light travels in one year

   

Correct Answer:  

Correct  

the distance that light travels in one year

   

Response Feedback:  

A light-year is the distance light will travel in one year.

 

 

.

Question 2  

.

3 out of 3 points

   

 

If you say that something is 3,000 light-years away, you are stating that ________.

 

Selected Answer:  

Correct  

the light that we see from the object traveled for 3,000 years before reaching our eyes

   

Correct Answer:  

Correct  

the light that we see from the object traveled for 3,000 years before reaching our eyes

   

Response Feedback:  

This means that we are seeing light that left the object 3,000 years ago.

 

 

.

Question 3  

.

2 out of 2 points

   

 

The phenomenon of cosmological redshift demonstrates that the universe is expanding.

 

Selected Answer:  

Correct  

TRUE

   

Correct Answer:  

Correct  

TRUE

   

Response Feedback:  

This statement is true.

 

 

.

Question 4  

.

2 out of 2 points

   

 

Galaxies moving away from us will emit light that is redder than we would otherwise expect.

 

Selected Answer:  

Correct  

TRUE

   

Correct Answer:  

Correct  

TRUE

   

Response Feedback:  

This statement is true.

 

 

.

Question 5  

.

3 out of 3 points

   

 

A star has a high apparent magnitude and a low absolute magnitude. This star is likely

 

Selected Answer:  

Correct  

close to Earth

   

Correct Answer:  

Correct  

close to Earth

   

Response Feedback:  

This star is close to Earth, making it appear very bright to us.

 

 

.

Question 6  

.

3 out of 3 points

   

 

The magnitude of a star is an expression of a star’s

 

Selected Answer:  

Correct  

brightness

   

Correct Answer:  

Correct  

brightness

   

Response Feedback:  

Magnitude is an expression of brightness.

 

 

.

Question 7  

.

3 out of 3 points

   

 

Which of the following describes the brightness of a star as we see it from Earth?

 

Selected Answer:  

Correct  

apparent magnitude

   

Correct Answer:  

Correct  

apparent magnitude

   

Response Feedback:  

This is the apparent magnitude.

 

 

.

Question 8  

.

0 out of 3 points

   

 

Stars may shine brighter or dimmer depending on their age. What else may affect how brightly we see a star’s light?

 

Selected Answer:  

Incorrect  

location of the moon in relation to the star

   

Correct Answer:  

Correct  

distance from the star

   

Response Feedback:  

The distance from a star also affects brightness.

 

 

.

Question 9  

.

3 out of 3 points

   

 

If we observe a star over 6 months and obtain a parallax angle (p) for the star, how can we calculate the distance to the star?

 

Selected Answer:  

Correct  

distance = 1/p

   

Correct Answer:  

Correct  

distance = 1/p

   

Response Feedback:  

Distance is 1/p.

 

 

.

Question 10  

.

3 out of 3 points

   

 

A star’s parallax angle is 0.8. How far away is the star in parsecs?

 

Selected Answer:  

Correct  

1.25

   

Correct Answer:  

Correct  

1.25

   

Response Feedback:  

Distance is 1/p.  

 


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What is the Gravitational Potential Energy of a 30 kg box lifted 1.5 meters off the ground?
juin [17]

Answer:

<h2>441 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 30 × 9.8 × 1.5

We have the final answer as

<h3>441 J</h3>

Hope this helps you

6 0
2 years ago
One speaker generates sound waves with amplitude A.
raketka [301]

Answer:

iv) It is 9x bigger than before

Explanation:

As the amplitudes of the new speakers add directly with the original one, taking into account the phase that they have, the composed amplitude of the sound wave is as follows:

At = A + 4A -2A = 3 A

The intensity of the wave, assuming it propagates evenly in all directions, is constant at a given distance from the source, and can be expressed as follows:

I = P/A

where P= Power of the wave source, A= Area (for a point source, is equal to the surface area of a sphere of radius r, where is r is the distance to the source along a straight line)

For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.

If the amplitude changes increasing three times, the change in intensity will be proportional to the square of the change in amplitude, i.e., it will be 9 times bigger.

So, the statement iv) is the right one.

7 0
3 years ago
Astronaut mark uri is space-traveling from planet x to planet y at a speed of relative to the planets, which are at rest relativ
lyudmila [28]
<span>From the point of view of the astronaut, he travels between planets with a speed of 0.6c. His distance between the planets is less than the other bodies around him and so by applying Lorentz factor, we have 2*</span>√1-0.6² = 1.6 light hours. On the other hand, from the point of view of the other bodies, time for them is slower. For the bodies, they have to wait for about 1/0.6 = 1.67 light hours while for him it is 1/(0.8) = 1.25 light hours. The remaining distance for the astronaut would be 1.67 - 1.25 = 0.42 light hours. And then, light travels in all frames and so the astronaut will see that the flash from the second planet after 0.42 light hours and from the 1.25 light hours is, 1.25 - 0.42 = 0.83 light hours or 49.8 minutes.
5 0
3 years ago
A boat moves through the water with two forces acting on it. One is a 1,800-N forward push by the water on the propeller, and th
baherus [9]

(a)The acceleration of the 1,400-kg boat will be 0.425 m/sec²

(b) If it starts from rest, the distance through which the boat moves in 20.0 s will be 85 m.

(c)Velocity at the end of that time will be 8.5 m/sec.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Given data;

Forwad force acting on the boat,v₁ = 1,800-N

Resistive force acting on the boat,v₂ = 1,200-N

The acceleration of the boat,a

Mass of boat,m = 1,400-kg

Initial velocity of boat,u= 0 m/sec

Distance travelled by boat,S = ?

Time for the boat travels,t = 20.0 s

Final velocity,V = ? m/sec

The net force on the boat;

F = F₁ - F₂

F = 1800 N - 1200 N

F = 600 N

From the defination of force;

F= ma

a = F / m

a = 600 N / 1400 kg

a = 0.425 m/sec²

b)

The distance through which the boat moves is 20.0 s;

\rm x_f = x_ 0 + v_0 t + \frac{1}{2} at^2 \\\\ x_f  = \frac{1}{2}at^2 \\\\ x_f = 0+0 + \frac{1}{2} at^2 \\\\ x_f = \frac{1}{2}\times 0.425 \times (20 )^ 2 \\\\ x_f  = 85 \ m

c)

The velocity at the end of that time is found as;

\rm  v_f = v_ 0 + at \\\\ v_f =- 0+ at \\\\ v_f = 8.5 m/sec

Hence the acceleration of the boat, the distance through which the boat moves in 20.0 s, and velocity at the end of that time will be 0.425 m/sec²,85 m, and 8.5 m/sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972

#SPJ1

8 0
2 years ago
A primary succession does not include any invasive species <br><br> True or false
yan [13]
To be referenced, it would be true
7 0
3 years ago
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