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2 years ago

Explain how rock D is the best rock

Physics

1 answer:

Naya [18.7K]2 years ago

7 0

The best rock is D because it is big and heavy out of all of them. Rock A would fling too far because it is the lightest of all rocks as shown.

B and C would probably fling through the target because it is just the right size.

Besides, Depending on their weight of each rock, rock D is heavy because it is big. Rock A is too light to fling or land on the target. This is my hypothesis.

I don't really get how would rock D be the best one, but upon your question, this is all i know.

Thank you for posting your question, hope this helps, have a great day. please mark brainliest so i can answer more of your questions.

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A roller coaster car rapidly picks up speed as it rolls down a slope. as it starts down the slope, its speed is 4 m/s. but 3 sec

Arisa [49]

Vi = 4 m/s
vf = 22 m/s
t = 3s
a = ?

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vf - vi = a * t
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2 years ago

A small electronic device is rated at 0.16 W when connected to 115 V. What is the resistance of this device?

Ierofanga [76]

Answer:

150156.25 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of electric current in a circuit. The S.I unit of resistance is Ohm's (Ω)

The expression for resistance is given as

P = V²/R................ equation 1

Where P = power, V = Voltage, R = Resistance.

Making R the subject of the equation,

R = V²/P.................. Equation 2

Given: V = 115 V , P = 0.16 W.

Substitute into equation 2

R = 155²/0.16

R = 150156.25 Ω

Hence,

The resistance = 150156.25 Ω

8 0

2 years ago

Read 2 more answers

How can accuracy be limited?

lozanna [386]

Answer:

accuracy refers to the deviation of a measurement from a standard or true value of the quantity being measured

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3 years ago

You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica

Pani-rosa [81]

Answer:

Length = 2.92 m

Diameter = 0.11 mm

Explanation:

We have $m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A}$ , where:

$l$ is the length

$m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3$

We divide the first equation by the second equation to get:

$\frac{m}{R} = \frac{d A^2}{\rho}$

$A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8} \ m^2$