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Sauron [17]
3 years ago
5

Explain how rock D is the best rock

Physics
1 answer:
Naya [18.7K]3 years ago
7 0
The best rock is D because it is big and heavy out of all of them. Rock A would fling too far because it is the lightest of all rocks as shown.

 B and C would probably fling through the target because it is just the right size. 

Besides, Depending on their weight of each rock, rock D is heavy because it is big. Rock A is too light to fling or land on the target. This is my hypothesis.

I don't really get how would rock D be the best one, but upon your question, this is all i know. 

Thank you for posting your question, hope this helps, have a great day. please mark brainliest so i can answer more of your questions. 
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Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after
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Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after the objects collide and bounce apart?

a-velocity

b-mass

c-momentum

d-direction

Answer:

b. Mass

Explanation:

This question has to do with the principle of the law of conservation of momentum which states that the momentum of a system remains constant if no external force is acting on it.

As the question states, two objects collide with each other and eventually bounce apart, so their momentum may not be conserved but the mass of the objects is constant for each non-relativistic motion. Because of this, the mass of each object prior to the collision would be the same as the mass after the collision.

Therefore, the correct answer is B. Mass.

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4 years ago
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5 0
3 years ago
A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the cloth
Alla [95]

Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

Given that,

Poles = 2

Distance = 16 m

Mass = 3 kg

Sags distance = 3 m

We need to calculate the angle made with vertical by mass

Using formula of angle

\tan\theta=\dfrac{8}{3}

\thta=\tan^{-1}\dfrac{8}{3}

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We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

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Put the value into the formula

3\times9.8=2T\times\cos69.44

T=\dfrac{3\times9.8}{2\times\cos69.44}

T=41.85\ N  

Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.

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