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Crazy boy [7]
3 years ago
12

Echolocation is based on the use of sound

Physics
2 answers:
shutvik [7]3 years ago
6 0

Answer: In echolocation, you use wave sounds to found objects:

A source emanates a wave of sound, and the sound travels in the medium, eventually rebounds on a wall or something, and the wave returns to the source.  Then the source is listening the echoes of the sound ( this is the motive of the name)

Now, if some object is between the walls and the source, then when the wave reaches that object, a small part of the wave will rebound first than the rest of it, and the thing using echolocation will know that there is an object and the exact position of the object.

This is something that some animals use to move in dark places, for example the bats use echolocation when they do that little noises in caves.

Anni [7]3 years ago
5 0
Yes echolocation is based on the use of sound and knowing where the sound comes from without having to look for it a lot of soldiers on the battle field need to know how to use echolocation so they can basically not die
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Which person will most likely hear the loudest sound?
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Person standing on A will hear the loudest sound

Explanation:

The intensity of a sound wave (which is proportional to the loudness of the sound) follows an inverse square law, which is:

I\propto \frac{1}{r^2}

where

I is the intensity of the wave

r is the distance from the source of the sound

This equation means that the intensity of the sound wave (and therefore, its loudness) is inversely proportional to the square of the distance  from the source: therefore,

  • As we get closer to the source of sound, the loudness increases
  • As we move away from the source of sound, the loudness decreases

Therefore, the person that will hear the loudest sound is the one standing closer to the source, and therefore person A.

Learn more about sound waves:

brainly.com/question/4899681

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3 years ago
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An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th
stepan [7]

Answer:

Number of photons travel through pin hole=6.4*10^{17}

Explanation:

First we will calculate the energy of single photon using below formula:

E=\frac{h*c}{λ}

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h is plank's constant with value 6.626*10^{-34} J.s

c is the speed of light whch is3*10^{8}

λ is the wave length = 532nm

E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}

E=3.73*10^{-19}J

Number of photons emitted per second:

\frac{5J/s}{1 photon/3.73*10^{-19} }

Number of photons emitted per second=1.34*10^{19} photons/s

\frac{A-hole}{A-beam}=\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

\frac{A-hole}{A-beam}=\frac{d-hole^2}{d-beam^2}

\frac{Ahole}{A-beam}=\frac{1.22^2}{5.5^2}

\frac{A-hole}{A-beam}=\frac{144}{3025}

Number of photons travel through pin hole=1.34*10^{19} *\frac{144}{3025}

Number of photons travel through pin hole=6.4*10^{17}

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