Answer:
a) 1450watts
b) 564watts
c) 1.11
Explanation:
Power consumed = IV
I is the current rating
V is the operating voltage
If a blow-dryer and a vacuum cleaner each operate with a voltage of 120 V and the current rating of the blow-dryer is 12 A, while that of the vacuum cleaner is 4.7 A then their individual power rating is calculated thus;
a) For blow-dryer
Operating voltage = 120V
Its current rating = 12A
Power consumed = IV
= 120×12
= 1440watts
b) For vacuum cleaner:
Operating voltage is the same as that of blow dryer = 120V
Its current rating = 4.7A
Power consumed = IV
= 120×4.7
= 564watts
c) Energy used = Power consumed × time taken
Energy used = Power × time
Energy used by blow dryer = 1440×20×60
= 1,728,000Joules
Energy used up by vacuum cleaner = 564×46×60
= 564×2760
= 1,556,640Joules
Ratio of the energy used by the blow-dryer in 20 minutes to the energy used by the vacuum cleaner in 46 minutes will be 1,728,000/1,556,640 = 1.11
Yes. There is a substantial number of people ... members of Brainly as well as non-members ... students, puzzle solvers, and just average educated thinkers, who would be able to solve it.
Answer: 28.96 V
Explanation:
Given
No of loops on the armature, N = 80
Length of the loop, l = 12 cm = 0.12 m
Width of the loop, b = 8 cm = 0.08 m
Speed of the armature, 1200 rpm
Magnetic field of the loop, B = 0.30 T
To solve this, we use the formula
V(max) = NBAω
Where,
A = area of loop
A = l*b = 0.12 * 0.08
A = 0.0096 m²
ω = 1200 rpm = 1200 * 2π/60 rad/s
ω = (1200 * 2 * 3.142) / 60
ω = 7540.8 / 60
ω = 125.68 rad/s
Substituting the values into the formula
V(max) = NBAω
V(max) = 80 * 0.30 * 0.0096 * 125.68
V(max) = 80 * 0.362
V(max) = 28.96 V
Therefore, the maximum output voltage of the generator would be 28.96 V
<span>From an area of higher conentration to an area of lower concentration which is B. my friend. Hoped i helped.
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