Explanation:
if we convert it into g/cm it'll be
2000 grams
Non metals are all the way on the right side
Metalloids are the stair case
Metals are on the left side
The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
<h3>What is the Inverse Square Law formula?</h3>
The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

Where
- I₁ = Intensity at distance 1 (W/m²)
- I₂ = Intensity at distance 2 (W/m²)
- d₁ = distance 1 from a light source (m)
- d₂ = distance 2 from a light source (m)
Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is




I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
Learn more about intensity of light here:
brainly.com/question/13155277
#SPJ4
Answer:
a) 0.477 W/m²
b) 13.407 N/C
c) 18.96 N/C
Explanation:
P = Power = 150 W
r = Distance = 5 m
ε₀ = Permittivity of space = 8.854×10⁻¹² F/m
a) Average intensity

∴ Average intensity is 0.477 W/m²
b) Rms value

∴ Rms value of the electric field is 13.407 N/C
c) Peak value

∴ Peak value of the electric field is 18.96 N/C
12-15 billion years i think