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alexandr1967 [171]
2 years ago
8

If 0.250 L of a gas weighs 0.308 g under normal conditions of pressure and temperature, what is its molecular weight?

Physics
1 answer:
Phantasy [73]2 years ago
8 0

Answer:

=28

Explanation:

.25/22=0,11 mol

0.308/0,11=28

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A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one
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Answer with Explanation:

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Resistance of copper wire=R=13\Omega

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If a wire has greater resistance then,the wire will be greater in length.

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r+7r=13

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r=\frac{13}{8}ohm

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Resistance of short piece of wire =\frac{13}{8}\Omega

Resistivity of wire and cross section area of wire remains same .

Let L be the total  length  of wire and L' be the length of short  piece of wire.

We know that

R=\frac{\rho L}{A}=\frac{\rho}{A}L=KL

\frac{R}{L}=K

Where K=\frac{\rho}{A}=Constant

Using the formula

\frac{13}{L}=\frac{\frac{13}{8}}{L'}

\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}

L'=\frac{L}{8}

Length of short piece of wire=L'=\frac{L}{8}

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% of length of short piece of   wire=\frac{\frac{L}{8}}{L}\times 100=12.5%%

The resistance of the short piece=\frac{13}{8}\Omega

The resistance of the long piece=\frac{91}{8}\Omega

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