If 0.250 L of a gas weighs 0.308 g under normal conditions of pressure and temperature, what is its molecular weight?
1 answer:
Answer:
=28
Explanation:
.25/22=0,11 mol
0.308/0,11=28
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Answer:
100m
Explanation:

u=0;t=10sec;a=2m/s²

s=10²;100m
Answer:
27.4
Explanation:
(13+43+12+3+66)/5
137/5
27.4
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