Answer:
19.2 m/s
Explanation:
The train is moving at 18 m/s and you are walking in the same direction (east) so the speeds are added
18 + 1.2 = 19.2
If you were walking backwards (west) your velocity with respect to the ground would be
18 - 1.2 = 16.8
Answer:
The coefficient of static friction between the puppy and the floor is 0.7273.
Explanation:
The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:
![F_s = \mu_s*N](https://tex.z-dn.net/?f=F_s%20%3D%20%5Cmu_s%2AN)
Where
is the static friction force,
is the coefficient of static friction and
is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore,
, to make the puppy moving we need to use a force of 80 N, therefore,
, so we can solve for the coefficient as shown below:
![80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\](https://tex.z-dn.net/?f=80%20%3D%20%5Cmu_s%2A110%5C%5C%5Cmu_s%20%3D%20%5Cfrac%7B80%7D%7B110%7D%20%3D%200.7273%5C%5C)
The coefficient of static friction between the puppy and the floor is 0.7273.
Answer:
An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0.
Explanation:
:)
Answer:
Explanation:
Acceleration is the rate of change of velocity. Usually, acceleration means the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is still accelerating, because the direction of its velocity is changing.
Answer:
F = 0.075 N
Explanation:
given,
diameter of ping pong ball = 2.55 cm
average density of the ball = 0.116 g/cm³
Force require to hold the ball completely submerged= ?
Volume of the ball
![V = \dfrac{4}{3} \pi r^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3)
![V = \dfrac{4}{3} \pi (\dfrac{2.55}{2})^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%20%28%5Cdfrac%7B2.55%7D%7B2%7D%29%5E3)
V = 8.63 cm³
density of water = 1 g/cm³
force required to keep the ball submerged is equal to
![F = \rho_w V_w g - \rho_b V g](https://tex.z-dn.net/?f=F%20%3D%20%5Crho_w%20V_w%20g%20-%20%5Crho_b%20V%20g%20)
![F = 1\times 8.63\times g - 0.116 \times 8.63 \times g](https://tex.z-dn.net/?f=F%20%3D%201%5Ctimes%208.63%5Ctimes%20g%20-%200.116%20%5Ctimes%208.63%20%5Ctimes%20g%20)
F = 7.63 x 9.8 x 10⁻³
F = 0.075 N
Force required to keep the ball inside the water is equal to 0.075 N