Answer:
c. 100 N
Explanation:
= mass of each = 55 kg
= Time period of rotation = 7.0 sec
Angular frequency is given as
= Diameter of the merry-go-round = 4.5 m
Radius of the merry-go-round is given as
Magnitude of outward force is same as the centripetal force and is given as
Answer:
Polarizing angle,
Given:
Critical angle,
Solution:
Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:
(1)
where
= refractive index of zirconia
From eqn (1):
Now, the angle of polarization is given by:
tan
Therefore,
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Explanation:
We can solve this problem by applying Newton's third law, which states that:
<em>"When an object A exerts a force (called </em><em>action</em><em>) on an object B, then object B exerts an equal and opposite force (called </em><em>reaction</em><em>) on object A"</em>
In this problem, we can identify:
- The sun as object A
- The planet as object B
By applying Newton's third law, we can state that:
- The action is the gravitational force exerted by the sun on the planet
- The reaction is the gravitational force exerted by the planet on the sun
According to the law, the two forces are equal in magnitude and opposite in direction: so, we can conclude that
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Learn more about Newton's third law:
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<span>The correct option is D) both A and B. In fact, the strength of an electric field produced by a single point charge is given by
</span>
<span>
where Q is the charge that generates the field, k is the Coulomb's constante and r is the distance from the charge source of the field.
From the equation, we see that the strength of the field depends on A) the amount of charge that produced the field (Q) and B) the distance from the charge (r), so the correct option is D.</span>