Answer:
Answer:
28.025 Nm
Explanation:
Angular acceleration, α = 29.5 rad/s^2
oment of inertia, I = 0.95 kg m^2
The torque is defined as
τ = I x α
τ = 0.95 x 29.5
τ = 28.025 Nm
Thus, the torque is 28.025 Nm.
Explanation:
Answer
given,
For helium
Volume,V = 46 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₁ = ?
number of moles
we know
P V = n R T
![n_1 =\dfrac{46 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_1%20%3D%5Cdfrac%7B46%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₁ = 1.89 moles
For oxygen
Volume,V = 12 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₂ = ?
number of moles
we know
P V = n R T
![n_2 =\dfrac{12 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_2%20%3D%5Cdfrac%7B12%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₂ = 0.49 moles
Total volume of tank = 5 L
temperature of tank = 298 K
Partial pressure of helium
![P_1=\dfrac{n_1 R T}{V}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7Bn_1%20R%20T%7D%7BV%7D)
![P_1=\dfrac{1.89\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B1.89%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₁ = 9.25 atm
Partial pressure of oxygen
![P_2=\dfrac{n_2 R T}{V}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7Bn_2%20R%20T%7D%7BV%7D)
![P_2=\dfrac{0.49\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B0.49%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₂ = 2.39 atm
total pressure
P = P₁ + P₂
P = 9.25 + 2.39
P = 11.64 atm
Gravity decreases your kinetic energy when you are driving uphill since the direction of motion is opposite for both. Driving uphill is force going upward while gravity pulls object down. When it is going downhill, the car tends to go faster since the gravity helps the object to go down by adding another value to the total acceleration of the motion of the object. Using the forces of balance, an object going up tends to become heavier while object going down tends to become lighter because of the gravity factor. Another analogy is the motion of elevators going up and down that incurs effects to your weiight.
Answer:
r = 58.44 [m]
Explanation:
To solve this problem we must use the following equation that relates the centripetal acceleration with the tangential velocity and the radius of rotation.
a = v²/r
where:
a = centripetal acceleration = 15.4 [m/s²]
v = tangential speed = 30 [m/s]
r = radius or distance [m]
r = v²/a
r = 30²/15.4
r = 58.44 [m]
156 is the answer. so 156.25 is almost the same thing, you just round. It's not hard. Thank you!!!