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andriy [413]
3 years ago
15

How high would a 75 kg hiker have to climb to increase her potention by 12000 J

Physics
1 answer:
LekaFEV [45]3 years ago
5 0

16.33m

Explanation:

Given parameters:

Mass of the hiker = 75kg

Potential energy = 12000J

Unknown:

Height = ?

Solution:

The potential energy is the energy at rest of a body.

   Potential energy =  mgh

m is the mass of the hiker

g is the acceleration due to gravity

h is the height

  The unknown is the height;

          Height = \frac{Potential energy}{mg}

           Height = \frac{12000}{75 x 9.8} = 16.33m

Learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

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Madelin fires a bullet horizontally. The rifle is 1.4 meters above the ground. The bullet travels 168 meters horizont before it
alex41 [277]

The position vector of the bullet has components

x=v_0t

y=1.4\,\mathrm m-\dfrac g2t^2

The bullet hits the ground when y=0, which corresponds to time t:

1.4\,\mathrm m-\dfrac g2t^2=0\implies t=0.53\,\mathrm s

The bullet travels 168 m horizontally, which would require a muzzle velocity v_0 such that

168\,\mathrm m=v_0(0.53\,\mathrm s)

\implies v_0\approx320\,\dfrac{\mathrm m}{\mathrm s}

4 0
4 years ago
Please Help Me!!!........​
-Dominant- [34]

Answer:

.b

Explanation:

3 0
3 years ago
If a proton with velocity v is inside a uniform magnetic field, the work done on the proton by the magnetic field is greater tha
Kipish [7]

Answer:

ZERO

Explanation:

As we know that force due to magnetic field on moving charge is given by

\vec F = q(\vec v \times \vec B)

now here we can say that the force due to magnetic field is always perpendicular to the velocity and it is also perpendicular to the magnetic field.

So we can say that

\vec F. \vec v = 0

so power due to magnetic field is always zero

which shows that rate of work done by magnetic field on moving charge is zero

so here the work done by magnetic field is always zero

7 0
4 years ago
Steam at 100°C is condensed into a 38.0 g steel calorimeter cup containing 220 g of water at 29.0°C. Determine the amount of ste
babunello [35]

Answer:

7.2 g (0.0072)g

Explanation:

Mass of calorimeter cup Mc = 38 g = 38 / 1000kg = 0.038 kg, mass of water in the calorimeter Mw =220g = 220/1000 kg = 0.22kg, initial temperature of the calorimeter and water = 29 oC, final temperature expected = 48oC

Using the formula

Heat gain = heat loss  assuming no heat is loss to the surrounding

Heat loss by steam = mLv  + mcΔT (heat loss in cooling the water to 48oC) where m is the mass of steam in kg, c is the specific heat capacity of water (4200J/(Kg.oC) and latent heat of vaporization of water = 22.6 × 10^5J/Kg is the heat loss in condensing water back to steam

Take m out as common and substitute the values into the above formula

Heat loss by steam = m (Lv + cΔT) = m (( -22.6 × 10^5) + ( 4200 × (48-100)))

Heat loss by steam = m ( -2260000 - 218400)

Heat loss by steam = m ( - 2478400) where the - sign signify loss

Heat gain by calorimeter and water inside = MccΔT + MwcΔT

substitute the values inside the formula

Heat gain by calorimeter and water = (0.038 ×490×(48-29)) + (0.22 ×4200×(48-29)

Heat gain by calorimeter and water = 353.7 + 17556 = 17909.78 J

Remember Heat gain equals heat loss

17909.78 = m (2478400)

divide both side by 2478400

m = 17909.78 / 2478400 = 0.0072 kg = 7.2  g

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3 years ago
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