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marishachu [46]
3 years ago
8

A weightlifter lifts a 1250-N barbell 2 m in 3 s.How much power was used to lift the barbell?

Physics
1 answer:
Vlad [161]3 years ago
5 0

The power is 833.3 W

Explanation:

First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:

W=(mg)h

where

mg = 1250 N is the weight of the barbell

h = 2 m is the change in height

Substituting,

W=(1250)(2)=2500 J

Now we can calculate the power, which is equal to the work done per unit time:

P=\frac{W}{t}

where

W = 2500 J is the work done

t = 3 s is the time taken

Substituting,

P=\frac{2500}{3}=833.3 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

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Answer:

B.) by interfering with sound waves

Explanation:

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2). destructive interference

now we know that constructive interference means the resultant intensity will be more than the intensity of interfering waves as here two waves are in same phase.

In destructive interference the resultant of two waves is given by the minimum resultant of the intensity as here the phase of two waves are opposite to each other.

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This will reduce the noise and we will get a clear sound

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During a lie detector test, a voltage of 6V is impressed across two fingers. When a certain question is asked, the resistance be
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The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

<u>Given data : </u>

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

<h3>Determine The Current </h3>

A) initially through fingers

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B) when the resistance between them drops

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