Answer:
no of unit is 17941
Explanation:
given data
fixed cost = $338,000
variable cost = $143 per unit
fixed cost = $1,244,000
variable cost = $92.50 per unit
solution
we consider here no of unit is = n
so here total cost of labor will be sum of fix and variable cost i.e
total cost of labor = $33800 + $143 n ..........1
and
total cost of capital intensive = $1,244,000 + $92.5 n ..........2
so here in both we prefer cost of capital if cost of capital intensive less than cost of labor
$1,244,000 + $92.5 n < $33800 + $143 n
solve we get
n > ![\frac{906000}{50.5}](https://tex.z-dn.net/?f=%5Cfrac%7B906000%7D%7B50.5%7D)
n > 17941
and
cost of producing less than selling cost so here
$1,244,000 + $92.5 n < 197 n
solve it we get
n >
n > 11904
so in both we get greatest no is 17941
so no of unit is 17941
Answer:
a) 180 m³/s
b) 213.4 kg/s
Explanation:
= 1 m²
= 100 kPa
= 180 m/s
Flow rate
![Q=A_1V_1\\\Rightarrow Q=1\times 180\\\Rightarrow Q=180\ m^3/s](https://tex.z-dn.net/?f=Q%3DA_1V_1%5C%5C%5CRightarrow%20Q%3D1%5Ctimes%20180%5C%5C%5CRightarrow%20Q%3D180%5C%20m%5E3%2Fs)
Volumetric flow rate = 180 m³/s
Mass flow rate
![\dot{m}=\rho Q\\\Rightarrow \dot m=\frac{P_1}{RT} Q\\\Rightarrow \dot m=\frac{100000}{287\times 293.15}\times 180\\\Rightarrow \dotm=213.94\ kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%3D%5Crho%20Q%5C%5C%5CRightarrow%20%5Cdot%20m%3D%5Cfrac%7BP_1%7D%7BRT%7D%20Q%5C%5C%5CRightarrow%20%5Cdot%20m%3D%5Cfrac%7B100000%7D%7B287%5Ctimes%20293.15%7D%5Ctimes%20180%5C%5C%5CRightarrow%20%5Cdotm%3D213.94%5C%20kg%2Fs)
Mass flow rate = 213.4 kg/s
Yes, it will. The induction will be the same as long as it’s put back together.
Answer:
Part A:
![1.3568*10^{-5}=\frac{5300* New\ CPI_1+11660*1+8480*4+1696*2}{2*10^9\ Hz} \\ New\ CPI_1=-4.12](https://tex.z-dn.net/?f=1.3568%2A10%5E%7B-5%7D%3D%5Cfrac%7B5300%2A%20New%5C%20%20CPI_1%2B11660%2A1%2B8480%2A4%2B1696%2A2%7D%7B2%2A10%5E9%5C%20Hz%7D%20%5C%5C%20New%5C%20CPI_1%3D-4.12)
CPI cannot be negative so it is not possible to for program to run two times faster.
Part B:
![1.3568*10^{-5}=\frac{5300*1+11660*1+8480*New\ CPI_3+1696*2}{2*10^9\ Hz} \\ New\ CPI_3=0.8](https://tex.z-dn.net/?f=1.3568%2A10%5E%7B-5%7D%3D%5Cfrac%7B5300%2A1%2B11660%2A1%2B8480%2ANew%5C%20CPI_3%2B1696%2A2%7D%7B2%2A10%5E9%5C%20Hz%7D%20%5C%5C%20New%5C%20CPI_3%3D0.8)
CPI reduced by
=80%
Part C:
New Execution Time=![\frac{5300*0.6+11660*0.6+8480*2.8+1696*1.4}{2*10^9\ Hz}=1.81472*10^{-5}\ s](https://tex.z-dn.net/?f=%5Cfrac%7B5300%2A0.6%2B11660%2A0.6%2B8480%2A2.8%2B1696%2A1.4%7D%7B2%2A10%5E9%5C%20Hz%7D%3D1.81472%2A10%5E%7B-5%7D%5C%20s)
Increase in speed=![1-\frac{1.81472*10^{-5}}{2.7136*10^{-5}} =0.33125= 33.125\%](https://tex.z-dn.net/?f=1-%5Cfrac%7B1.81472%2A10%5E%7B-5%7D%7D%7B2.7136%2A10%5E%7B-5%7D%7D%20%3D0.33125%3D%2033.125%5C%25)
Explanation:
FP Instructions=50*106=5300
INT Instructions=110*106=11660
L/S Instructions=80*106=8480
Branch Instructions=16*106=1696
Calculating Execution Time:
Execution Time=![\frac{\sum^4_{i=1} Number\ of\ Instruction*\ CPI_{i}}{Clock\ Rate}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csum%5E4_%7Bi%3D1%7D%20Number%5C%20of%5C%20Instruction%2A%5C%20CPI_%7Bi%7D%7D%7BClock%5C%20Rate%7D)
Execution Time=![\frac{5300*1+11660*1+8480*4+1696*2}{2*10^9\ Hz}](https://tex.z-dn.net/?f=%5Cfrac%7B5300%2A1%2B11660%2A1%2B8480%2A4%2B1696%2A2%7D%7B2%2A10%5E9%5C%20Hz%7D)
Execution Time=![2.7136*10^{-5}\ s](https://tex.z-dn.net/?f=2.7136%2A10%5E%7B-5%7D%5C%20s)
Part A:
For Program to run two times faster,Execution Time (Calculated above) is reduced to half.
New Execution Time=![\frac{2.7136*10^{-5}}{2}=1.3568*10^{-5}\ s](https://tex.z-dn.net/?f=%5Cfrac%7B2.7136%2A10%5E%7B-5%7D%7D%7B2%7D%3D1.3568%2A10%5E%7B-5%7D%5C%20s)
![1.3568*10^{-5}=\frac{5300* New\ CPI_1+11660*1+8480*4+1696*2}{2*10^9\ Hz} \\ New\ CPI_1=-4.12](https://tex.z-dn.net/?f=1.3568%2A10%5E%7B-5%7D%3D%5Cfrac%7B5300%2A%20New%5C%20%20CPI_1%2B11660%2A1%2B8480%2A4%2B1696%2A2%7D%7B2%2A10%5E9%5C%20Hz%7D%20%5C%5C%20New%5C%20CPI_1%3D-4.12)
CPI cannot be negative so it is not possible to for program to run two times faster.
Part B:
For Program to run two times faster,Execution Time (Calculated above) is reduced to half.
New Execution Time=![\frac{2.7136*10^{-5}}{2}=1.3568*10^{-5}\ s](https://tex.z-dn.net/?f=%5Cfrac%7B2.7136%2A10%5E%7B-5%7D%7D%7B2%7D%3D1.3568%2A10%5E%7B-5%7D%5C%20s)
![1.3568*10^{-5}=\frac{5300*1+11660*1+8480*New\ CPI_3+1696*2}{2*10^9\ Hz} \\ New\ CPI_3=0.8](https://tex.z-dn.net/?f=1.3568%2A10%5E%7B-5%7D%3D%5Cfrac%7B5300%2A1%2B11660%2A1%2B8480%2ANew%5C%20CPI_3%2B1696%2A2%7D%7B2%2A10%5E9%5C%20Hz%7D%20%5C%5C%20New%5C%20CPI_3%3D0.8)
CPI reduced by
=80%
Part C:
![New\ CPI_1=0.6*Old\ CPI_1=0.6*1=0.6\\New\ CPI_2=0.6*Old\ CPI_2=0.6*1=0.6\\New\ CPI_3=0.7*Old\ CPI_3=0.7*4=2.8\\New\ CPI_4=0.7*Old\ CPI_4=0.7*2=1.4](https://tex.z-dn.net/?f=New%5C%20CPI_1%3D0.6%2AOld%5C%20CPI_1%3D0.6%2A1%3D0.6%5C%5CNew%5C%20CPI_2%3D0.6%2AOld%5C%20CPI_2%3D0.6%2A1%3D0.6%5C%5CNew%5C%20CPI_3%3D0.7%2AOld%5C%20CPI_3%3D0.7%2A4%3D2.8%5C%5CNew%5C%20CPI_4%3D0.7%2AOld%5C%20CPI_4%3D0.7%2A2%3D1.4)
New Execution Time=![\frac{\sum^4_{i=1} Number\ of\ Instruction*\ CPI_{i}}{Clock\ Rate}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csum%5E4_%7Bi%3D1%7D%20Number%5C%20of%5C%20Instruction%2A%5C%20CPI_%7Bi%7D%7D%7BClock%5C%20Rate%7D)
New Execution Time=![\frac{5300*0.6+11660*0.6+8480*2.8+1696*1.4}{2*10^9\ Hz}=1.81472*10^{-5}\ s](https://tex.z-dn.net/?f=%5Cfrac%7B5300%2A0.6%2B11660%2A0.6%2B8480%2A2.8%2B1696%2A1.4%7D%7B2%2A10%5E9%5C%20Hz%7D%3D1.81472%2A10%5E%7B-5%7D%5C%20s)
Increase in speed=![1-\frac{1.81472*10^{-5}}{2.7136*10^{-5}} =0.33125= 33.125\%](https://tex.z-dn.net/?f=1-%5Cfrac%7B1.81472%2A10%5E%7B-5%7D%7D%7B2.7136%2A10%5E%7B-5%7D%7D%20%3D0.33125%3D%2033.125%5C%25)