Answer:
The answer to this question is 1273885.3 ∅
Explanation:
<em>The first step is to determine the required hydraulic flow rate liquid if working pressure and if a cylinder with a piston diameter of 100 mm is available.</em>
<em>Given that,</em>
<em>The distance = 50mm</em>
<em>The time t =10 seconds</em>
<em>The force F = 10kN</em>
<em>The piston diameter is = 100mm</em>
<em>The pressure = F/A</em>
<em> 10 * 10^3/Δ/Δ </em>
<em> P = 1273885.3503 pa</em>
<em>Then</em>
<em>Power = work/time = Force * distance /time</em>
<em> = 10 * 1000 * 0.050/10</em>
<em>which is =50 watt</em>
<em>Power =∅ΔP</em>
<em>50 = 1273885.3 ∅</em>
The amount of work done by steady flow devices varies with the particular gas volume. The kinetic energy of gas particles decreases during cooling.
When the gas is subjected to intermediate cooling during compression, the gas specific volume is reduced, which lowers the compressor's power consumption. Compression is less adiabatic and more isothermal because the compressed gas must be cooled between stages since compression produces heat. The system's thermodynamic cycle's cold sink temperature is lowered by cooling the compressor coils. By increasing the temperature difference between the heat source and the cold sink, this improves efficiency.
Learn more about thermodynamics here-
brainly.com/question/1368306
#SPJ4
Answer:
A.
Explanation:
Individual footings are the commonest, and they are often used if the load of the building is borne by columns. Typically, every column will have an own footing. The footing is usually only a rectangular or square pad of concrete on which the column is erected
Answer:Counter,
0.799,
1.921
Explanation:
Given data
![T_{h_i}=200^{\circ}C](https://tex.z-dn.net/?f=T_%7Bh_i%7D%3D200%5E%7B%5Ccirc%7DC)
![T_{h_o}=120^{\circ}C](https://tex.z-dn.net/?f=T_%7Bh_o%7D%3D120%5E%7B%5Ccirc%7DC)
![T_{c_i}=100^{\circ}C](https://tex.z-dn.net/?f=T_%7Bc_i%7D%3D100%5E%7B%5Ccirc%7DC)
![T_{c_o}=125^{\circ}C](https://tex.z-dn.net/?f=T_%7Bc_o%7D%3D125%5E%7B%5Ccirc%7DC)
Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger
Equating Heat exchange
![m_hc_{ph}\left [ T_{h_i}-T_{h_o}\right ]=m_cc_{pc}\left [ T_{c_o}-T_{c_i}\right ]](https://tex.z-dn.net/?f=m_hc_%7Bph%7D%5Cleft%20%5B%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%5D%3Dm_cc_%7Bpc%7D%5Cleft%20%5B%20T_%7Bc_o%7D-T_%7Bc_i%7D%5Cright%20%5D)
=![\frac{125-100}{200-120}=\frac{25}{80}=C\left ( capacity rate ratio\right )](https://tex.z-dn.net/?f=%5Cfrac%7B125-100%7D%7B200-120%7D%3D%5Cfrac%7B25%7D%7B80%7D%3DC%5Cleft%20%28%20capacity%20rate%20ratio%5Cright%20%29)
we can see that heat capacity of hot fluid is minimum
Also from energy balance
![Q=UA\Delta T_m=\left ( mc_p\right )_{h}\left ( T_{h_i}-T_{h_o}\right )](https://tex.z-dn.net/?f=Q%3DUA%5CDelta%20T_m%3D%5Cleft%20%28%20mc_p%5Cright%20%29_%7Bh%7D%5Cleft%20%28%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%29)
=![\frac{\left ( T_{h_i}-T_{h_o}\right )}{T_m}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%20%28%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%29%7D%7BT_m%7D)
![T_m=\frac{\left ( 200-125\right )-\left ( 120-100\right )}{\ln \frac{75}{20}}](https://tex.z-dn.net/?f=T_m%3D%5Cfrac%7B%5Cleft%20%28%20200-125%5Cright%20%29-%5Cleft%20%28%20120-100%5Cright%20%29%7D%7B%5Cln%20%5Cfrac%7B75%7D%7B20%7D%7D)
![T_m=41.63^{\circ}C](https://tex.z-dn.net/?f=T_m%3D41.63%5E%7B%5Ccirc%7DC)
NTU=1.921
![And\ effectiveness \epsilon =\frac{1-exp\left ( -NTU\left ( 1-c\right )\right )}{1-c\left ( -NTU\left ( 1-c\right )\right )}](https://tex.z-dn.net/?f=And%5C%20effectiveness%20%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-NTU%5Cleft%20%28%201-c%5Cright%20%29%5Cright%20%29%7D%7B1-c%5Cleft%20%28%20-NTU%5Cleft%20%28%201-c%5Cright%20%29%5Cright%20%29%7D)
![\epsilon =\frac{1-exp\left ( -1.921\left ( 1-0.3125\right )\right )}{1-0.3125exp\left ( -1.921\left ( 1-0.3125\right )\right )}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-1.921%5Cleft%20%28%201-0.3125%5Cright%20%29%5Cright%20%29%7D%7B1-0.3125exp%5Cleft%20%28%20-1.921%5Cleft%20%28%201-0.3125%5Cright%20%29%5Cright%20%29%7D)
![\epsilon =\frac{1-exp\left ( -1.32068\right )}{1-0.3125exp\left ( -1.32068\right )}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-1.32068%5Cright%20%29%7D%7B1-0.3125exp%5Cleft%20%28%20-1.32068%5Cright%20%29%7D)
![\epsilon =\frac{1-0.2669}{1-0.0834}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-0.2669%7D%7B1-0.0834%7D)
![\epsilon =0.799](https://tex.z-dn.net/?f=%5Cepsilon%20%3D0.799)
Answer:
use the dimensions shown in the figure