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katrin2010 [14]
3 years ago
14

What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C?

Chemistry
1 answer:
Oksanka [162]3 years ago
8 0
The specific heat capacity  the substance is calculated  using  the below formula

Q(heat) = Mc delta T
Q =1560  cal
m(mass) 312 g
delta T (change in temperature ) = 15 c
C= specific heat capacity=?

by making c the subject of the formula 
c=Q/m delta T
= 1560  cal/ 312g x 15 c = 0.33 cal/g/c (answer B)


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Q= 4.184 \frac{J}{g*C} * 45 g* 17.5 C

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Q=3,294.9 J

<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>

<u><em></em></u>

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