Question

Solve log(3+2log(1+x)) =0

Answer 1

Assuming $\log x\equiv\log_{10}x$,

$\log(3+2\log(1+x))=0$
$10^{\log(3+2\log(1+x))}=10^0$
$3+2\log(1+x)=1$
$2\log(1+x)=-2$
$\log(1+x)=-1$
$10^{\log(1+x)}=10^{-1}$
$1+x=\dfrac1{10}$
$x=-\dfrac9{10}$