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umka2103 [35]
4 years ago
13

Please help me explain why D has the solution x=-3 thank you

Mathematics
1 answer:
Serggg [28]4 years ago
7 0
The best way to solve these types of equations is to plug the solution in and see if it checks out.
1/2x+8=10
1/2*-3+8=10
-1.5+8=10
6.5 is not equal to 10
1/2(2*-3-6)=-6
1/2(-6-6)=-6
1/2*(-12)=-6
-6=-6
so d checks out

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The quotient of negative Eight and the sum of a number and three
geniusboy [140]
(x÷ - 8 )(x-3) i think that is the answer 

7 0
3 years ago
How did they get m=29?????
eduard

That is not the specified answer

They Actually mentioned the value of 'm'

<em>and in the second sentence of the question they substituted the value of 'm' that is 29 ( whích ís αlrєαdч gívєn ín thє quєstíσn )</em>

6 0
3 years ago
Which function is a quadratic function? y – 3x2 = 3(x2 + 5) + 1 y2 – 7x = 2(x2 + 6) + 7 y – 2x2 = 6(x3 + 5) – 4 y – 5x = 4(x + 5
Anna71 [15]

Answer:

Option A.

Step-by-step explanation:

The general form of a quadratic function is  

y=ax^2+bx+c

It means, power of y should be 1 and highest power of x should be 2.

In option A,

y-3x^2=3(x^2+5)+1

y-3x^2=3x^2+15+1

y=3x^2+16+3x^2

y=6x^2+16

It is a quadratic function.

In option B,

y^2-7x=2(x^2+6)+7

Here, power of y is 2. So, it is not be a quadratic function.

In option C,

y-2x^2=6(x^3+5)

Here, highest power of x is 3. So, it is not be a quadratic function.

In option D,

y-5x=4(x+5)+9

Here, highest power of x is 1. So, it is not be a quadratic function.

Therefore, the correct option is A.

7 0
4 years ago
PLEASE HELP!!!
AfilCa [17]

Answer:

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

JP=5\sqrt{3}\ cm

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

h=\dfrac{a\sqrt{3}}{2},

where a is the side length.

So,

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

Therefore JP is 5√3 cm

3 0
3 years ago
What is seen in the middle of March and April that can’t be seen at the beginning or end of either month?
Troyanec [42]

Answer:

That I have no idea what it is. sorry

Step-by-step explanation:

7 0
3 years ago
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