Answer:
Step-by-step explanation:
g³ + g² - 12g ≠ 0
g(g² + g - 12) ≠ 0
g(g - 3)(g + 4) ≠ 0
g ≠ 0
g ≠ 3
g ≠ - 4
Answer:
(2,-6) and (4,-16)
Step-by-step explanation:
-5x+4 crosses these points
The mean is calculated by adding up all of the data points and then dividing the sum by the amount of points added.
The mean fitness score was 3.2 points. If all of the students scored the same thing (3.2 points) then this would be the fitness score of each student.
Thus, the answer is D. 3.2 points.
It would go 880 km in 11 hours, and it would take 14 hours to go 1120 km
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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