1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
3 years ago
5

2 Chemistry Questions. Help?

Chemistry
1 answer:
Sliva [168]3 years ago
3 0
<span>C-C and C-H bonds are relatively stable because 

they have low bond dissociation energy 


13. Dispersion forces are caused by the __________, 

motion of electrons 

Hope this answers the question. Have a nice day.</span>
You might be interested in
What are conversion factors in chemistry?
jenyasd209 [6]
A conversion factor is ALWAYS equal to 1 :)
5 0
3 years ago
Dimethyl sulfide is the most abundant biological sulfur compound emitted to the atmosphere. It is produced by phytoplankton and
iogann1982 [59]

The structure of Dimethyl sulfide is H3C-S-CH3. It is produced naturally by some marine algae.

<u>Explanation:</u>

  • DMS or dimethyl sulfide is formed by using two methyl groups combined with one sulfur atom. It is an organosulphur compound with a structural formula H3C-S-CH3.
  • Most abundant biological sulfur compounds emitted to air and oceans by phytoplankton.
  • DMS is produced naturally by the waste of dimethyl sulphoxide which is disposed into the sewer causing environmental odor problems.
  • It is a flammable liquid that boils at 37 degrees celsius and a disagreeable smell produced from the cooking of certain vegetables also indicates bacterial contamination in the production of malt and brewing.

6 0
3 years ago
Which product of the ultraviolet decomposition of cfcs acts as the catalyst for ozone decomposition?
Vikentia [17]
The answer is <span>Chlorine atoms.   This is the </span><span>product of the ultraviolet decomposition of cfcs acts as the catalyst for ozone decomposition.  </span>
8 0
3 years ago
TIMED PLS HELP AND WILL GIVE BRAINLIST
Strike441 [17]

Answer:

19.4 g of alum, will be its theoretical yield

Explanation:

The reaction is:

2 Al + 2 KOH + 4 H₂SO₄ + 22H₂O → 3H₂ + 2KAl(SO₄)₂•12H₂O

Let's determine the amount of acid.

M are the moles contained in 1 L of solution or it can be mmoles that are contained in 1 mL of solution

M = mmol /mL

M . mL = mmol

We replace: 8.3 mL . 9.9 M = 82.17 mmoles

We convert to moles: 82.17 mmol . 1 mol / 1000mmol = 0.082 moles

Ratio is 4:2

4 moles of sulfuric acid can make 2 moles of alum

By the way, 0.082 moles of acid may produce ( 0.082 . 2) /4 = 0.041085 moles.

We convert moles to mass:

Molar mass of alum is: 473.52 g/mol.

0.041085 moles . 473.52 g/mol = 19.4 g

6 0
3 years ago
Pls this need this I am doing a test and I need to get this
Alexxx [7]

Answer:

nib7tttugi

Explanation:

ilbbu

6 0
3 years ago
Other questions:
  • What is the initial
    6·1 answer
  • One of the physical properties of metal is that it is malleable. What does malleable mean? Question 2 options: shiny Thick and h
    14·1 answer
  • Describe the three states of matter
    15·2 answers
  • For the noble gases (the Group 8A elements) 4He2, 20Ne10, 40Ar18, 84Kr36 and 132Xe54, (a) determine the number of protons and ne
    7·1 answer
  • Which of the following is not an example of a molecule?
    14·2 answers
  • If there is 15.00 grams of magnesium in the reaction what quantity of sodium will be produced
    9·1 answer
  • What was the purpose of letting the transformed cells sit in LB for a few minutes before spreading them onto the plates?
    11·1 answer
  • 18.74 g of P4 is reacted with 9.6 g of Cl2 balanced is P4 (s) + 6 Cl2 (g) → 4 PCl3 (l) how many PlC3 can I make?
    11·1 answer
  • When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and
    5·1 answer
  • 1. if the barometer reading is recorded to be higher than the actual value. what effect does this error have on the reported val
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!