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2 years ago

2 Chemistry Questions. Help?

1 answer:

3 0

C-C and C-H bonds are relatively stable because

they have low bond dissociation energy

13. Dispersion forces are caused by the __________,

motion of electrons

Hope this answers the question. Have a nice day.

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Hi can you slove this please. ..

Crank

Answer : The balanced chemical equation will be:

(i) $2K+H_2SO_4\rightarrow K_2SO_4+H_2$

(ii) $Mg(OH)_2+Zn\rightarrow Zn(OH)_2+Mg$

Explanation :

Balanced chemical equation : It is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

Part (i):

The balanced chemical equation will be:

$2K+H_2SO_4\rightarrow K_2SO_4+H_2$

This reaction is a single displacement reaction in which most reactive element (potassium) displaces the least reactive element (hydrogen) form their solution.

Part (ii):

The balanced chemical equation will be:

$Mg(OH)_2+Zn\rightarrow Zn(OH)_2+Mg$

This reaction is a single displacement reaction in which most reactive element (zinc) displaces the least reactive element (magnesium) form their solution.

7 0

3 years ago

Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO

Irina-Kira [14]

Answer : The enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $H_2SO_4$ will be,

$S+H_2+2O_2\rightarrow H_2SO_4$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $S+O_2\rightarrow SO_2$ $\Delta H_1=-298.2$

(2) $SO_2+\frac{1}{2}O_2\rightarrow SO_3$ $\Delta H_2=-98.2$

(3) $SO_3+H_2O\rightarrow H_2SO_4$ $\Delta H_3=-130.2$

(4) $H_2+\frac{1}{2}O_2\rightarrow H_2O$ $\Delta H_4=-285.8$

Now adding all the equations, we get the expression for enthalpy of formation of $H_2SO_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4$

$\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)$

$\Delta H=-812.4kJ/mol$

Therefore, the enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

3 0

3 years ago

What are the 4 major macromolecules

ANEK [815]

Carbohydrates
Lipids
Protein
Nucleic acids

8 0

3 years ago

A sample of table sugar (sucrose c12h22o11) has a mass of 3.115 g

attashe74 [19]

Hey there:

a) atomic mass:

Carbon =12.0107 g/mol

Hydrogen = 1.00794 g/mol

Oxygen = 15.9994 g/mol

Therefore:

C12H22O11 =

12 * 12.0107 + 1 * 1.00794 + 16 * 15.9994 => 342.29648 g/mol

__________________________________________________________

b) number of moles:

n = m / mm

n = 3.115 / 342.29648

n = 0.0091 moles

________________________________________________

hope this helps!

6 0

3 years ago

Nuclei with ______ numbers of neutrons and protons are more stable . A low

FinnZ [79.3K]

Answer: equal

Explanation:

I believe the answer is equal but i would need more context.

7 0

3 years ago