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Simora [160]
3 years ago
12

How would one go about solving this?? Thank you. ​

Chemistry
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:

5.66g/ml

Explanation:

Mass of Metal Slug, m = 25.17g

Volume of container (flask), v = 59.7ml

Mass of Methanol, M = 43.7g with density, d = 0.791g/ml

Therefore,

Volume of Methanol = M/d = 43.7 / 0.791 = 55.25ml

Volume of Metal slug in the flask = v - V = 59.7 - 55.25 = 4.45ml

Density of Metal slug = mass of metal slug / volume of metal slug

                                   = 25.17 / 4.45 = 5.66g/ml

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Answer:

b) pH = 9.25

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⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature

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⇒ M NH4+ = [ NH4+ ] - [ OH- ]

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⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5

⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6

⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0

⇒ [ OH- ] = 1.859 E-5 M

⇒ pOH = - Log ( 1.859 E-5 )

⇒ pOH = 4.7305

⇒ pH = 14 - pOH = 9.269

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