The information that the coefficients of a balanced equation give about the reactants are to tell how many moles of reactants are needed and how many moles of product can be produced.
The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:
Q = N x ΔH
where:
Q = heat
N = moles
ΔH = enthalpy
In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:
1. Calculate moles of water
2. multiply by the enthalpy of fusion
3. Convert kJ to J.
Step 1 : Calculate moles of water
![[ 75g ] x (\frac{1 mol}{18.02g} ) =](https://tex.z-dn.net/?f=%5B%2075g%20%5D%20x%20%28%5Cfrac%7B1%20mol%7D%7B18.02g%7D%20%29%20%3D)
Step 2 : Multiply by enthalpy of fusion
Q = N × ΔH = <em> [ Step 1 Answer ]</em> × 6.02 =
Step 3 : Convert kJ to J
![[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =](https://tex.z-dn.net/?f=%5B%20Step%202%20Answer%20%5D%20x%20%28%5Cfrac%7B1000j%7D%7B1kJ%7D%20%29%20%3D)
Finally rounding to 2 sig figs (since 34°C has two sig figs) we get
Q Would Equal ____
<em><u /></em>oxidation i say 33333333333333333333333
The decreasing order of the mass of the molecules are:
Fe2O3>C6H14>CaCO>NO2
Explanation:
Let us calculate the atomic mass of the molecules given:
C6H14 Atomic mass of 1 carbon atom =12.01 amu
so, 6*12+1*14 Atomic mass of hydrogen=1.007
= 86 g/mol
Atomic mass of NO2
= 14+ (2*15.9)
= 14+ 31.8
= 45.8 g/mol
Atomic mass of Fe203
( 2*55.845)+ (3*15.9)
= 159.69 g/mol
Atomic mass of CaCO
40.07+12.0107+15.99
= 68.07g/mol
The decreasing order of the mass of the molecules are:
Fe2O3>C6H14>CaCO>NO2