The three things that are necessary are power, a force, and movement in the opposite direction of the applied force.
Answer:
b = 5.164 m is the minimum thickness of the dam
Explanation:
Given
SG = 5
h = 20 m
b = ?
w = 1 m
γw = 9800 N/m³
We can get the forces as follows
Fp = γw*(h/2)*(h*w)
⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N
W = (SG*γw)*(h*b*w)
⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b
Then, we apply
∑M₀ = 0 (counterclockwise)
- Fp*(h/3) + W*(b/2) = 0
⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0
- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0
⇒ b = 5.164 m is the minimum thickness of the dam
Answer:
In Newtonian mechanics, the gravitational energy possessed by a mass, because of the gravitational field produced by a second mass.
Explanation:
Answer:
the maximum mass that can hang without sinking is 2.93 kg
Explanation:
Given: details:
sphere diameter d = 20 cm
so, radius r = 10 cm = 0.10 m
density of the Styrofoam sphere D = 300 kg/m3
sphere volume 

=4.18*10^{-3} m^3
we know that

mass M = Density * Volume
= (300)(4.18*10^{-3} m3)
=1.25 kg
mass of the water displace = volume *density of water
= 4.18*10^{-3} m3 * 1000
= 4.18 kg
The difference between the mass of water and mass of styrofoam is the amount of mass that the sphere can support
=4.18 kg -1.25 kg
= 2.93 kg