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fomenos
3 years ago
7

Convert the speed of light 3.0x10^8 m/s to km/day

Physics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer: 2.592 \times 10^{8}km/day

1 m = 0.001 km\\ 1 s= 1.157\times10^{-5} days\\ 1 m/s = \frac {0.001}{1.157\times10^{-5}} km/day = 86.4 km/day \\ 3.0\times 10^{8} m/s = 3.0\times 10^{8} m/s \times \frac {86.4 km/day}{1m/s} =2.592 \times 10^{8}km/day



just olya [345]3 years ago
6 0

Answer:

2592*10^7\frac{km}{day}.

Explanation:

We need to know that 1km = 1000 m= 10^3m and 1 day = 86400 = 864 * 10^2s.

3*10^8 \frac{m}{s} = 3*10^8\frac{m}{s} \frac{86400 s}{1 day}

= 3*10^8*864*10^2\frac{m}{day} = 2592 * 10^{10} \frac{m}{day}

Now, 2592 * 10^{10} \frac{m}{day}\frac{1km}{10^3m}

= 2592 * 10^{10}*10^{-3}\frac{km}{day} = 2592*10^7\frac{km}{day}.

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