A scientist shines light from a source onto a piece of metal, and no electrons are released by the metal. Increasing the intensi
1 answer:
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Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
a E =
b E =
c E = 0 N/C
d
e
f V =
g
h
i
Explanation:
From the question we are given that
The first charge
The second charge
The first radius
The second radius
And
The objective is to obtain the the magnitude of electric for different cases
And the potential difference for other cases
Considering a
r = 4.00 m
Considering b
This implies that the electric field would be
This because it the electric filed of the charge which is below it in distance that it would feel
=
Considering c
r = 0.200 m
=>
The electric field = 0
This is because the both charge are above it in terms of distance so it wont feel the effect of their electric field
Considering d
r = 4.00 m
=>
Now the potential difference is
This so because the distance between the charge we are considering is further than the two charges given
Considering e
r = 1.00 m
Considering f
Considering g
Considering h
Considering i
