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aev [14]
2 years ago
9

A scientist shines light from a source onto a piece of metal, and no electrons are released by the metal. Increasing the intensi

ty of the light source does not change this result. What is this effect, and how do scientists explain it?
This is the Doppler effect, and it is best explained by the wave model of light.,

This is the Doppler effect, and it is best explained by the particle model of light.


This is the photoelectric effect, and it is best explained by the wave model of light.,

This is the photoelectric effect, and it is best explained by the particle model of light.
Physics
1 answer:
Nezavi [6.7K]2 years ago
7 0

This is the photoelectric effect, and it is best explained by the particle model of light.

<h3>What is the photoelectric effect?</h3>

The photoelectric effect refers to the emission of negatively charged particles and electromagnetic radiation that hits an object.

The photoelectric effect shows how electrons can be released from a given object when this material is absorbing electromagnetic radiation.

The photoelectric effect is a fundamental piece of evidence for understanding the nature of light particles.

Learn more about the photoelectric effect here:

brainly.com/question/1359033

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Ultraviolet light having a wavelength of 97 nm strikes a metallic surface. Electrons leave the surface with speeds up to 3.48 ×
irga5000 [103]

Answer:

<h2><em>12.45eV</em></h2>

Explanation:

Before calculating the work function, we must know the formula for calculating the kinetic energy of an electron. The kinetic energy of an electron is the taken as the difference between incident photon energy and work function of a metal.

Mathematically, KE =  hf - Ф where;

h is the Planck constant

f is the frequency = c/λ

c is the speed of light

λ is the wavelength

Ф is the work function

The formula will become KE =  hc/λ - Ф. Making the work function the subject of the formula we have;

Ф = hc/λ - KE

Ф = hc/λ - 1/2mv²

Given parameters

c = 3*10⁸m/s

λ = 97*10⁻⁹m

velocity of the electron v = 3.48*10⁵m/s

h = 6.62607015 × 10⁻³⁴

m is the mass of the electron = 9.10938356 × 10⁻³¹kg

Substituting the given parameters into the formula Ф = hc/λ - 1/2mv²

Ф =  6.63 × 10⁻³⁴*3*10⁸/97*10⁻⁹ -  1/2*9.11*10⁻³¹(3.48*10⁵)²

Ф = 0.205*10⁻¹⁷ - 4.555*10⁻³¹*12.1104*10¹⁰

Ф = 0.205*10⁻¹⁷ - 55.163*10⁻²¹

Ф = 0.205*10⁻¹⁷ - 0.0055.163*10⁻¹⁷

Ф = 0.1995*10⁻¹⁷Joules

Since 1eV = 1.60218*10⁻¹⁹J

x = 0.1995*10⁻¹⁷Joules

cross multiply

x = 0.1995*10⁻¹⁷/1.60218*10⁻¹⁹

x = 0.1245*10²

x = 12.45eV

<em>Hence the work function of the metal in eV is 12.45eV</em>

6 0
3 years ago
Which force causes a wagon to speed up as it rolls down a hill?
Temka [501]
Gravity is the only one helping it.
7 0
3 years ago
Read 2 more answers
BRAINLIEST PLEASE HELP ASAP DO NOT ANSWER UNLESS YOU KNOW AND DON'T GIVE ME A LINK OR I WILL REPORT YOU
Korvikt [17]

Answer:

In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.

Explanation:

3 0
2 years ago
On May 26, 1934, a streamlined, stainless steel diesel train called the Zephyr set the world’s nonstop long-distance speed recor
Andre45 [30]

Answer:

124.88 km/h

34.69 m/s

Explanation:

1633.8 km = 1633800 m

13 hours 4 minutes 58 seconds = 13 + 4/60 + 58/3600 = 13.083 hours

13 hours 4 minutes 58 seconds = 13*3600 + 4*60 + 58 = 47098 seconds

So the average speed in km/h is

1633.8 / 13.083 = 124.88 km/h

The average speed in m/s is

1633800 / 47098 = 34.69 m/s

8 0
3 years ago
A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini
Grace [21]

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, m_1=4\ kg

Mass of dove, m_2=1\ kg

Initial velocity of falcon, u_1=3\ m/s

Initial velocity of dove, u_2=2\ m/s

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V is the velocity after impact

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{4\times 3+1\times 2}{(4+1)}

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

7 0
3 years ago
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