Answer:
m = 39834.3 g
Explanation:
Given data:
Mass of water raised = ?
Initial temperature = 25°C
Final temperature = 37°C
Energy added = 2000 Kj (2000 ×1000= 2000,000 j
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 37°C - 25°C
ΔT = 12°C
c = 4.184 g/j.°C
Q = m.c. ΔT
2000,000j = m .4.184 g/j.°C. 12°C
2000,000j = m. 50.208 g/j
m = 2000,000j / 50.208 g/j
m = 39834.3 g
Answer:
91.5 mol
Explanation:
Volume of gas = 70 L
Temperature = 25°C
Pressure = 32 atm
Moles of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273.15 = 298.15 K
By putting values,
32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K
2240 atm.L = n ×24.48 atm.L /mol
n = 2240 atm.L / 24.48 atm.L /mol
n = 91.5 mol
Answer:
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:
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Answer:
hunting for other animals or when they are really hungry
Explanation:
