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Arisa [49]
3 years ago
14

Urine, with a ph of 6, is _________ times more acidic than seawater, with a ph of 8.?

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
6 0
The correct answer is 100. Hope I helped! :]
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HELPPP ME WITH SICENCE PLZZZZZZ
Goryan [66]

Answer:

molecules

Explanation:

molecules because the summer like atoms and Sciences sciency to be honest

7 0
3 years ago
Read 2 more answers
In step 2, of the experiment, the procedure uses 3.0M NaOH. However, the student notices that the only solution of NaOH is conce
Luda [366]

Answer:

We need 78.9 mL of the 19.0 M NaOH solution

Explanation:

Step 1: Data given

Molarity of the original NaOH solution = 19.0 M

Molarity of the NaOH solution we want to prepare = 3.0 M

Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L

Step 2: Calculate volume of the 19.0 M NaOH solution needed

C1*V1 = C2*V2

⇒with C1 = the concentration of the original NaOH solution = 19.0 M

⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M

⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

19.0 M * V2 = 3.0 M * 0.500 L

V2 = (3.0 M * 0.500L) / 19.0 M

V2 = 0.0789 L

We need 0.0789 L

This is 0.0789 * 10^3 mL = 78.9 mL

We need 78.9 mL of the 19.0 M NaOH solution

8 0
3 years ago
Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a m
AysviL [449]

Answer:

0.1828g/cm³

Explanation:

density= mass÷volume

m= 12.6g

v= 4.1×4.1×4.1 = 68.921cm³

•

density= 12.6÷68.921 = 0.1828g/cm³

6 0
3 years ago
Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Which are the basic oxides among these? b) What is the name o
umka2103 [35]
<h3>Further explanation</h3>

Basic oxides ⇒ metal(usually alkali/alkaline earth) +O₂

L + O₂ ⇒ L₂O

L + O₂ ⇒ LO

Dissolve in water becomes = basic solution

L₂O+H₂O⇒ 2LOH

LO + H₂O⇒ L(OH)₂

So the basic oxides : Na₂O and MgO

Na₂O + H₂O⇒NaOH

MgO +H₂O⇒Mg(OH)₂

The aqueous solution of CO₂(dissolve in water)

CO₂ + +H₂O⇒ H₂CO₃(carbonic acid)

5 0
3 years ago
Ascorbic acid, or vitamin C (C6H8O6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant propert
nydimaria [60]

Answer : 50.69 mg of ascorbic acid does not meet the daily requirement.

Solution : Given,

Molar mass of Ascorbic acid = 176 g/mole

Moles of Ascorbic acid = 2.88\times 10^{-4}moles

Formula used :

Moles=\frac{Mass}{\text{ Molar mass}}

or, \text{ Mass of ascorbic acid}=\text{ Moles of ascorbic acid}\times \text{ Molar mass of ascorbic acid}

Now put all the given values in this formula, we get the mass of ascorbic acid.

\text{ Mass of ascorbic acid}=(2.88\times 10^{-4}moles)\times (176g/mole)=0.050688g=50.69mg

Conversion : (1g=1000mg)

As per question, a healthy adult’s daily requirement of vitamin C is 70-90 mg. But calculate mass of vitamin C is 50.69 mg. So, 50.69 mg of ascorbic acid does not meet the daily requirement.

5 0
3 years ago
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