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daser333 [38]
3 years ago
7

A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of t

he truck, is pushed along the length of the ramp. If the ramp is 4.5 m long and friction between the ramp and crate can be ignored, what is the mechanical advantage of the ramp?
Physics
1 answer:
const2013 [10]3 years ago
8 0

Answer: M.A = 3

Explanation:

A ramp is an example of an inclined plain. Where the

Height H = 1.5 m

Length L = 4.5 m

Mechanical advantage of a machine is the ratio of the load to effort. While mechanical advantage M.A of an inclined plain is the ratio of the length of the plain to the height of the plain.

M.A = L/H

Substitute the values of L and H into the formula

M.A = 4.5/1.5 = 3

The mechanical advantage of the ramp is 3

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Monochromatic light of variable wavelength is incident normally on a thin sheet of plastic film in air. The reflected light is a
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Answer:

thickness t = 528.433 nm

Explanation:

given data

wavelength λ1 = 477.1 nm

wavelength λ2 = 668.0 nm

n = 1.58

solution

we know for constructive interference condition will be

2 × t × μ = (m1+0.5) × λ1     ....................1

2 × t × μ = (m2+0.5) × λ2     ....................2

so we can say from equation 1 and 2

(m1+0.5) × λ1 = (m2+0.5) × λ2

so

\frac{\lambda 2}{\lambda 1} = \frac{m1+0.5}{m2+0.5}     ..............3

put here value and we get  

\frac{668.0}{477.1} = \frac{m1+0.5}{m2+0.5}  

\frac{m1+0.5}{m2+0.5}   = 1.4

\frac{m1+0.5}{m2+0.5}  = \frac{7}{5}   ...................4

so we here from equation 4

m1+0.5  = 7

m1 = 3    .................5

m2+0.5 = 4

m2 = 2    .................6

so now put value in equation  1

2 × t × μ = (m1+0.5) × λ1

2 × t × 1.58 = (3+0.5) ×  477.1

solve it we get

thickness t = 528.433 nm

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The topsoil layer has the greatest concentration of organic matter. The subsoil generally lacks organic matter, but it does rece
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because i did it on study island

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KATRIN_1 [288]
M, mass=84 kg
height, h=3.9m
gravity, g= 9.8m/s2
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F=force
d=Displacement
W=work done by force
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F= m g (Acting downward )
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