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masha68 [24]
3 years ago
14

According to accepted atomic models metals are good conductors because their?

Physics
1 answer:
grin007 [14]3 years ago
7 0
<span>According to accepted atomic models, the reason that metals are good conductors is because they have free electrons in their outer shell that are free to roam, therefore allowing for higher levels of conductivity than nonmetallic materials.</span>
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Can someone help me with the motion maps, I don't understand what I am supposed to write in the description or how to draw the a
Ugo [173]

Answer:

i  d  k

Explanation:

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3 years ago
The joule and the kilowatt-hour are both units of energy. 15 kw · h is equivalent to how many joules? answer in units of j.
choli [55]

The solution for the problem is:

1 Watt = 1 Joule per second 
1 Watt*second = 1 Joule 

a Kilowatt is 1,000 Watts 
an hour is 60 seconds times 60 minutes or 3,600 seconds 
a Kilowatt * hour is 1,000 Watts in 3,600 seconds 

15 W*h = 15,000 Watt*hour = 15,000 Watt * 3,600 seconds = 54,000,000 Watt*second 

54,000,000 Watt*second = ? Joules 
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3 0
3 years ago
The field lines around one end of a bar magnet are shown
Vlad1618 [11]

Answer:

Explanation:

Field lines are lines of forces around a bar magnet. The show the direction of force field in a magnet.

Usually, around a bar magnet, the field lines originates and spreads out from the north pole.

Then they converge and enter through the south pole.

Therefore, we can make our choice by inspecting the given diagram. If the lines enters through the pole, it is the south pole.

Where they originate or leave is the north pole.

7 0
3 years ago
Read 2 more answers
A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

f=12GHz=12\cdot 10^9 Hz is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

So the wavelength of the beam is

\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

y=\frac{m\lambda D}{a}

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m

and so, the diameter is

d=2y = 750 m

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

r=\frac{750 m}{2}=375 m

So the area is

A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2

And since the power is

P=100 kW = 1\cdot 10^5 W

The average intensity is

I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2

4 0
3 years ago
How far will an object move in 6 s if its average
Dafna11 [192]

Given:-

  • Time taken by the particle (t) = 6 s
  • Average speed (v) = 40 m/s

To Find: Distance (s) travelled by the particle.

We know,

s = vt

where,

  • s = Distance travelled,
  • v = Speed &
  • t = Time taken.

Putting the values,

s = (40 m/s)(6 s)

→ s = 240 m ...(Ans.)

6 0
3 years ago
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