3 years ago

Why is the weight of an object more on Earth than on the Moon?

Physics

1 answer:

JulijaS [17]3 years ago

8 0

<span>Why is the weight of an object more on Earth than on the Moon? i would say c</span>

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A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic

rodikova [14]

Answer:

KE= 1/2 * mass * Velocity^2

Explanation:

1/2 * 72.0kg* 79^2 m/s = 224676 J

4 0

3 years ago

The lesser the mass, the greater the acceleration for the given value of force. Why does this happen?

Tju [1.3M]

Newtons law states F=ma
so F/m=a
in addition it makes logical sense the lighter an object the easier it is to accelerate its velocity form 0 to some quantity

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3 years ago

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Kryger [21]

Answer:

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3 years ago

5- A 2500g object is pushed with 55N for 12m in 11s, there was a force of friction of 30N.

Assoli18 [71]

Answer:

1kg =1000g

2.5kg

D=12m

t=11s

F=2.5KG

Explanation:

work done =f.d

=2.5×12

=30Nm

55-30

average speed

final - initial

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3 0

2 years ago

A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.

iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2$

Converting to m/s²

$a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

$\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g$

Hence, acceleration of the car is -0.64525g

8 0

3 years ago