1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zolol [24]
3 years ago
9

Why is the weight of an object more on Earth than on the Moon?

Physics
1 answer:
JulijaS [17]3 years ago
8 0
<span>Why is the weight of an object more on Earth than on the Moon? i would say c</span>
You might be interested in
Which of the following is not a rock? a. granite c. marble b. shale d. diamond
bekas [8.4K]
The correct answer is  D, Diamond 
8 0
3 years ago
Read 2 more answers
Photo used to help with the question is below!! Please answer! Will mark BRAINLIEST!
Alisiya [41]

Answer:

refraction

Explanation: hope this helps :)

3 0
3 years ago
Read 2 more answers
Question 4
bagirrra123 [75]

That's <em>false</em>.  It's just the opposite.  As you become more fit, your heart becomes able to accomplish more with each beat, so your resting heart rate DEcreases.

4 0
3 years ago
A resistor is connected in series with an AC source that provides a sinusoidal voltage of v of t is equal to V times cosine of b
nekit [7.7K]
<h2>Answer:</h2>

In circuits, the average power is defined as the average of the instantaneous power  over one period. The instantaneous power can be found as:

p(t)=v(t)i(t)

So the average power is:

P=\frac{1}{T}\intop_{0}^{T}p(t)dt

But:

v(t)=v_{m}cos(\omega t) \\ \\ i(t)=i_{m}cos(\omega t)

So:

P=\frac{1}{T}\intop_{0}^{T}v_{m}cos(\omega t)i_{m}cos(\omega t)dt \\ \\ P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}cos^{2}(\omega t)dt \\ \\ But: cos^{2}(\omega t)=\frac{1+cos(2\omega t)}{2}

P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}(\frac{1+cos(2\omega t)}{2} )dt \\\\P=\frac{v_{m}i_{m}}{T}\intop_{0}^{T}[\frac{1}{2}+\frac{cos(2\omega t)}{2}]dt \\\\P=\frac{v_{m}i_{m}}{T}[\frac{1}{2}(t)\right|_0^T +\frac{sin(2\omega t)}{4\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2T}[(t)\right|_0^T +\frac{sin(2\omega t)}{2\omega} \right|_0^T] \\ \\ P=\frac{v_{m}i_{m}}{2}

In terms of RMS values:

V_{RMS}=V=\frac{v_{m}}{\sqrt{2}} \\ \\ I_{RMS}=I=\frac{i_{m}}{\sqrt{2}} \\ \\ Then: \\ \\ P=VI

7 0
3 years ago
What is the difference between soldering and solder? <br>​
andrey2020 [161]

Answer:

Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.

Explanation:

<em>Hope this helps :)</em>

<em>Pls mark brainliest :3 </em>

<em>And have an amazing day <3 </em>

4 0
2 years ago
Read 2 more answers
Other questions:
  • A drag racer starts her car from rest and accelerates at 11.9 m/s2 for the entire distance of 400 m. What is the speed of the ra
    12·1 answer
  • lood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobi
    12·1 answer
  • In a liquid with a density of 1400 kg/m3 , longitudinal waves with a frequency of 370 Hz are found to have a wavelength of 8.40
    14·1 answer
  • A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 610 N horizontal force to set it in motion. After the clo
    14·1 answer
  • An example of a constant acceleration is
    14·2 answers
  • The ability to do work or cause change is called
    7·1 answer
  • How much energy (in kW-h) does a 900 Watt stove use in a week if it is used for 1.5 hours each day?
    9·1 answer
  • Gold has a density of 19300 kg/m3 calculate the mass of 0.02m3 of gold in kilograms​
    12·1 answer
  • If positive work is being done to an object...
    14·1 answer
  • 8. Placing your vehicle between the pilot/escort vehicle and an oversize/overweight vehicle can be dangerous.A. TrueB. False
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!