A baseball flying through the air has what kind of energy?

How can a magnetic field be produced, using a wire, a battery, and and a nail?

Aleks [24]

It is fairly easy to build an electromagnet. All you need to do is wrap some insulated copper wire around an iron core. If you attach a battery to the wire, an electric current will begin to flow and the iron core will become magnetized. When the battery is disconnected, the iron core will lose its magnetism. Follow these steps.
Step 1 - Gather the Materials
One iron nail fifteen centimeters (6 in) long
Three meters (10 ft) of 22 gauge insulated, stranded copper wire
One or more D-cell batteries
Step 2 - Remove some Insulation
Step 3 - Wrap the Wire Around the Nail
Step 4 - Connect the Battery

5 0

3 years ago

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What's earths most precious element?

atroni [7]

I believe the answer is californium because it is used in most metals and is very strong and expensive like gold and silver

3 0

3 years ago

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Which question cannot be answered through making measurements?

Margarita [4]

Answer: it would be A

Explanation: how are we to measure the air of a square mile

8 0

4 years ago

a whistle you use to call your hunting dog has a frequency of 21 khz, but your dog is ignoring it. you suspect the whistle may n

laila [671]

To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as

$f = f_0 (\frac{v-v_0}{v})$

Here,

$f_0$ = Original frequency

$v_0$ = Velocity of the observer

$v$ = Velocity of the speed

Our values are,

$v = 340m/s \rightarrow \text{Speed of sound}$

$f = 20kHz \rightarrow \text{Apparent frequency}$

$f_0 = 21kHz \rightarrow \text{Original frequency}$

Using the previous equation,

$f = f_0 (\frac{v-v_0}{v})$

Rearrange to find the velocity of the observer

$v_0 =v (1-\frac{f}{f_0})$

Replacing we have that

$v_0= (340m/s)(1-\frac{20kHz}{21kHz})$

$v_0 = 16.19m/s$

Therefore the velocity of the observer is 16.2m/s

4 0

3 years ago

A rock of mass 200 g is attached to a 0.75 m long string and swung in a vertical plane.

Ainat [17]

Hello!

a) Assuming this is asking for the minimum speed for the rock to make the full circle, we must find the minimum speed necessary for the rock to continue moving in a circular path when it's at the top of the circle.

At the top of the circle, we have:

- Force of gravity (downward)

*Although the rock is still connected to the string, if the rock is swinging at the minimum speed required, there will be no tension in the string.

Therefore, only the force of gravity produces the net centripetal force:

$\Sigma F = F_g\\\\F_c = F_g\\\\\frac{mv^2}{r} = mg$