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yarga [219]
3 years ago
6

A baseball flying through the air has what kind of energy?

Physics
1 answer:
Sindrei [870]3 years ago
6 0
Kinetic energy is your answer

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By Faraday’s Law, if a conducting wire of length ℓ meters moves at velocity v m/s perpendicular to a magnetic field of strength
sasho [114]

Answer

given,

conducting wire  length =  ℓ m = 0.5

moves at velocity =  v m/s = v ( t ) = 4 t + 9

magnetic field strength = B  = 2 T

V = − B ℓ v

V = - 2 × 0.5 × v

V = - v

a) \dfrac{dV}{dv} = \dfrac{d(-v)}{dv}

   \dfrac{dV}{dv} = -1

b) given

    v ( t ) = 4 t + 9

    V = (-1)(4t + 9)

   \dfrac{dV}{dt} = \dfrac{d((-1)(4t + 9))}{dt}

   \dfrac{dV}{dv} = -4

3 0
3 years ago
Why does water’s high specific heat make it a good coolant for car radiators?.
Alexeev081 [22]

Answer:

Car radiators: Water is used as coolant car radiators. Due to its high specific heat capacity, it can absorb a large amount of heat energy from the engine of the car, but its temperature does not rise too high.

Explanation:

i hope this answer your question if it s wrong please let know

7 0
2 years ago
Read 2 more answers
What equation links charge flow, current and time?<br> I will award Brainliest if CORRECT!
Aliun [14]

Answer:

Q=it

Explanation:

\purple {\bold {Q = it}} is the equation equation that links charge flow, current and time.

Here,

Q = Charge

i = current

t = time

4 0
3 years ago
Gravitational potential energy is often released by burning substances. true or false
jolli1 [7]
Gravitational potential energy is caused when an object is resting above the ground. It is released when the object is falling, not by burning substances.
4 0
3 years ago
Read 2 more answers
How much energy is released when the correct number of protons and neutrons come together to form deuterium? a) 0.52 MeV b) 1.7
irga5000 [103]

<u>Answer:</u> The correct answer is 2.24 MeV.

<u>Explanation:</u>

The chemical reaction for the formation of deuterium from proton and neutron follows:

_{1}^1\textrm{H}+_0^1\textrm{n}\rightarrow _1^2\textrm{H}

We are given:

Mass of _{1}^{1}\textrm{H} = 1.00784 u

Mass of _{0}^{1}\textrm{n} = 1.008665 u

Mass of _{1}^{2}\textrm{H} = 2.014102 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

\Delta m=(m_{_1^2H}+m_{n})-(m_{_1^2H})\\\\\Delta m=(1.00784+1.008665)-(2.014102)=0.002403u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.002403u)\times c^2

E=(0.002403u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=2.24MeV

Hence, the energy released in the given nuclear reaction is 2.24 MeV.

5 0
3 years ago
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