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sertanlavr [38]
3 years ago
13

The 94-lb force P is applied to the 220-lb crate, which is stationary before the force is applied. Determine the magnitude and d

irection of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left.
Physics
1 answer:
Makovka662 [10]3 years ago
8 0

Answer

given,

force = 94 lb

weight of crate = 220 lb

Assuming the static friction be equal = 0.47

                       kinetic friction = 0.36

Maximum force applied to move the object is when object is just start to move.

F = μ N

F = 0.47 x 220

F = 103.4 lb

As the frictional force is more than applied then the object will not move.

so, the friction force will be equal to the force applied on the object that is equal to 94 lb.

hence, the direction of force will left.

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3 years ago
On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. The children push off of
sasho [114]

The velocity of the girl is  -4.8 m/s.

Using the principle of conservation of linear momentum, The total momentum of  bodies before and after collision is constant. Since the two objects are stationary, the initial momentum of each body is zero.

Thus;

0 = (80 × 3) + (50 × v)

0 = 240 + 50 v

-240 = 50 v

v = -240/50

v = -4.8 m/s

Note that the negative sign shows that the velocity of the girl is in opposite direction that that of the girl.

Learn more about momentum: brainly.com/question/904448

5 0
3 years ago
A light horizontal spring has a spring constant of 138 N/m. A 3.35 kg block is pressed against one end of the spring, compressin
BARSIC [14]

Answer:

U_k = 0.113

Explanation:

using the law of the conservation of energy:

E_i -E_f=W_f

\frac{1}{2}Kx^2=NU_kd

where K is the spring constant, x is the spring compression, N is the normal force of the block, U_k is the coefficiet of kinetic friction and d is the distance.

Also, by laws of newton, N is calculated by:

N = mg

N = 3.35 kg * 9.81 m/s

N = 32.8635

So, Replacing values on the first equation, we get:

\frac{1}{2}(138)(0.123)^2= (32.8635)U_k(0.281m)

solving for U_k:

U_k = 0.113

8 0
3 years ago
You are driving a car with an automatic transmission; the shifter is mounted on the steering column. When you press down on the
castortr0y [4]

Answer:

From the narrative in the question, there seem to have been a break failure and the ordered step of response to this problem is to

1) Put on the hazard light to inform other road users of a problem or potential fault with your car and so they should continue their journey with caution.

2) Avoid pressing on the acceleration pedal as this might cause the car to gradually slow down due to friction and gravity

3)Try navigate the car to the service lane. This is the less busy lane where cars are sometimes parked briefly.

4) Continuously pump the breaks to try stop the car. Continuously pumping the breaks might just help you build enough pressure to stop the car because often time, there are some pressure left in the break.

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3 years ago
75 kg + 1352 g = ______________g?
JulsSmile [24]
Answer is 76,352 just look it up
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3 years ago
Read 2 more answers
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