You must assume that the mass of the rocket and engine remains constant - even though the engine is burning.
You know the engine produces 13.8N for a distance of 14.6m
The total energy expended (work done) by the engine is FxD so you can calculate that
Now - some of that is given to the rocket as kinetic and potential energy, and some is expended against the drag force.
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh
So
Energy given to rocket = mgh
Energy expended by engine = F x D (D= height where engine stops)
Energy 'lost' to drag is the difference between the two values.
Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :



Work done on the wagon is given by the product of net force and displacement. It is given by :


W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.
Answer:
The work done is 10.64Joules
The acceleration is 
Explanation:
We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:

where:
is the resultant force acting on the object
m is its mass
a is its acceleration
In this problem, we have the following forces acting on the system:
(forward)
(backward)
So, Newton's second law can be rewritten as:

where:
m = 1050 kg is the mass of all the students
Solving the formula for a, we find the acceleration of the system:

Learn more about Newton's second law:
brainly.com/question/3820012
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To solve this problem, we know that:
1 psi = 6894.76 Pa
1 lb / ft^2 = 47.88 Pa
Therefore:
a. 1500 x 10^3 Pa * (1 lb / ft^2 / 47.88 Pa) = 31,328.32 lb
/ ft^2
b. 1500 x 10^3 Pa * (1 psi / 6894.76 Pa) = 217.56 psi